这就是我要实现的目标:用户使用旋转编码器输入时间。当用户继续旋转编码器时,Arduino串行显示器必须显示时间的实时值。然后,用户点击物理开关(推动开关(以启动倒计时。最初,我的代码与delay()
功能完美搭配。但是,我的应用程序还要求我运行电动机,只要计时器持续。为此,我需要一个非阻滞延迟。我很难过。请帮忙。这是我的代码:
unsigned long previousMillis = 0; // will store last time LED was updated
// constants won't change:
const long interval = 1000; // interval at which to blink (milliseconds)
#define outputA 6
#define outputB 7
int i;
int button=5;
int counter = 0;
int aState;
int aLastState;
void setup() {
pinMode (outputA,INPUT);
pinMode (outputB,INPUT);
pinMode (button,INPUT);
Serial.begin (9600);
// Reads the initial state of the outputA
aLastState = digitalRead(outputA);
}
void loop() {
// here is where you'd put code that needs to be running all the time.
aState = digitalRead(outputA); // Reads the "current" state of the outputA
// If the previous and the current state of the outputA are different, that means a Pulse has occured
if (aState != aLastState) {
// If the outputB state is different to the outputA state, that means the encoder is rotating clockwise
if (digitalRead(outputB) != aState) {
counter = counter+1;
} else {
counter = counter-1;
}
Serial.print("Time (secs): ");
Serial.println(counter);
i = counter;
if (digitalRead(button) == HIGH) {
while (i != 0) {
unsigned long currentMillis = millis();
if (currentMillis - previousMillis == interval) {
// save the last time you blinked the LED
previousMillis = currentMillis;
i--;
Serial.println(i);
}
}
}
aLastState = aState;
}
}
如果我了解很好,则仅在输入if (currentMillis - previousMillis == interval)
时降低i
。这意味着您的减少非常缓慢,而不是毫秒毫秒……
要纠正我建议:
unsigned long startMillis = millis();
while (millis() - startMillis() < counter){ //check if your time has elapsed
unsigned long currentMillis = millis();
if (currentMillis - previousMillis == interval) {
// save the last time you blinked the LED
previousMillis = currentMillis;
Serial.println((int) counter - (millis() - startMillis()));
}
}
希望它有帮助!