我正在构建一个用户统计信息页面并尝试正确显示统计信息,并希望得到一些帮助。
我有一个为注册用户提供可下载文件的网站,我想跟踪下载情况,每个用户下载该文件的次数以及他们从中下载了多少独特的产品。
表:customer_statistics
| user | product_id | file_download | date_accessed |
------------------------------------------------------------
| tom | 1104 | mp3 | 2017-05-06 00:00:00 |
| tom | 1048 | video | 2017-05-06 00:00:00 |
| tom | 1048 | video | 2017-05-06 00:00:00 |
| tom | 1048 | video | 2017-05-07 00:00:00 |
| tom | 1048 | video | 2017-05-08 00:00:00 |
| tom | 1010 | video | 2017-05-08 00:00:00 |
| tom | 1077 | video | 2017-05-08 00:00:00 |
| sue | 1749 | photo | 2017-05-09 00:00:00 |
| sue | 1284 | video | 2017-05-09 00:00:00 |
| sue | 1284 | video | 2017-05-09 00:00:00 |
| sue | 1065 | mp3 | 2017-05-09 00:00:00 |
| sue | 1344 | video | 2017-05-10 00:00:00 |
| sue | 2504 | photo | 2017-05-10 00:00:00 |
我会这样显示数据:
Name | Unique Mp3s | Unique Photos | Unique Videos | Total
----------------------------------------------------------
Tom | 1 | 0 | 3 | 7
Sue | 1 | 2 | 2 | 6
列unique mp3s/photos/videos
显示从每种文件类型下载的唯一product_id
数,而total
显示该特定用户的所有文件类型和出现次数的总数。
实现上述结果的最佳方法是什么?
提前感谢一堆!
我会这样做,不需要子查询:
SELECT user AS `Name`,
COUNT(DISTINCT CASE file_download WHEN 'mp3' THEN product_id END) AS `Unique Mp3s`
COUNT(DISTINCT CASE file_download WHEN 'photo' THEN product_id END) AS `Unique Photos`
COUNT(DISTINCT CASE file_download WHEN 'video' THEN product_id END) AS `Unique Videos`
COUNT(DISTINCT product_id) AS `Total`
FROM customer_statistics
GROUP BY user;