如何访问Symfony表单的原始提交数据?

Question

我正在使用一些Symfony表单，需要访问最初提交(未触及(的数据。数据访问器方法$form->getData()、$form->getViewData()和$form->getModelData()都为我提供了已经转换的值，但我需要PRE_SUBMIT事件中的数据。

我可以编写一个侦听器并在PRE_SUBMIT上提取它们，但是我必须将此信息存储在任何地方，并在使用该表单的服务中访问它。目前，我的服务只看到传递的表单对象，并且在没有其他依赖项的情况下完成其工作。

其他解决方法包括从请求对象读取。看起来不像一个明智的选项，因为表单可能是从其他来源填充的(如会话，它是一个过滤器表单(。

是否有直接从表单对象访问最初提交的数据的"官方"方法？如果没有，是否值得功能请求？对此有什么意见吗？

(我的用例是一个过滤器表单，其中状态存储在会话中并从会话中检索。由于提交表单时可能没有来自涉及 HTML-POST、HTML-GET 和 JSON-POST 模式的请求的数据，因此我不想只存储请求数据。

编辑2018-06-07：根据评论中的要求，我提供了一个代码示例：

/**
* handles the filterForm request reading POST-data or namespaced JSON payload with POST method or any standard form request
*
* @param FormInterface $filterForm
* @return void
* @throws ResponseException
*/
public function handleRequest(FormInterface $filterForm): void
{
// reset the filter state in the session, if a reset_filter query parameter was set
if (true === $this->request->query->getBoolean('reset_filter', false)) {
$this->setFilterState(null, $this->request->attributes->get('_route'));
$this->filterIsActive = true;
}
// handle filter submission in json context
if ($this->request->isMethod('POST') && $this->request->attributes->get('_format') === 'json') {
if ($this->request->get($filterForm->getName())) {
$submitData = $this->request->get($filterForm->getName());
}
else {
$postData = JsonHelper::parseAndCheckJsonPostData($this->request);
if ($postData instanceof Response) {
throw new ResponseException($postData);
}
$submitData = $postData[$filterForm->getName()] ?? null;
}
if (null !== $submitData) {
dump($submitData);
$filterForm->submit($submitData, true);
dump($filterForm->getData());
}
}
else {
// @todo find a smooth way to get the original submitted data of a form, when it is handled by the default handleRequest()-menthod
$submitData = null;
$filterForm->handleRequest($this->request);
}
// load the filter state from the session and submit it, if it is not yet set and we are in HTML context
if (!$filterForm->isSubmitted()
&& $this->request->attributes->get('_format') === 'html'
&& null !== $this->getFilterState($this->request->attributes->get('_route'))
) {
$filterForm->submit($this->getFilterState($this->request->attributes->get('_route')));
}
if ($filterForm->isSubmitted()) {
$this->filterIsActive = true;
// return an JSON error-document, if the filter form is not valid
if (!$filterForm->isValid() && $this->request->attributes->get('_format') === 'json') {
throw new ResponseException(
new JsonResponse([
'type' => 'error',
'message' => $this->translator->trans('Form.Filter.errorMessage'),
'filterForm' => $this->serializer->normalize($filterForm->createView()),
], Response::HTTP_BAD_REQUEST)
);
}
// store the new filter state, if filter is active and and valid
if ($filterForm->isValid() && null !== $submitData) {
$this->setFilterState($submitData, $this->request->attributes->get('_route'));
}
}
}

输出此内容：

array:4 [▼
"singleEntity" => "1"
"multipleEntities" => array:1 [▼
0 => "1"
]
"dateRange" => array:2 [▼
"left_date" => "06.06.2018"
"right_date" => "07.06.2018"
]
"submit" => true
]
array:11 [▼
"singleEntity" => MySingleEntity {#3739 ▶}
"facilities" => ArrayCollection {#3419 ▼
-elements: array:1 [▼
0 => MyMultiEntity {#3799 ▶}
]
}
"createdOrUpdatedBetween" => array:2 [▼
"left_date" => DateTime @1528236000 {#3408 ▼
date: 2018-06-06 00:00:00.0 Europe/Berlin (+02:00)
}
"right_date" => DateTime @1528322400 {#3397 ▼
date: 2018-06-07 00:00:00.0 Europe/Berlin (+02:00)
}
]
]

Answer 1

我有两个选项如何保存提交的数据

1( 直接从请求中获取

$submitted_data = [];
foreach ($form->all() as $child) {
if ($request->request->has($child->getName())) {
$submitted_data[$child->getName()] = $request->request->get($child->getName());
}
}

2( 使用表单事件

$submitted_data = null;
$formBuilder->addEventListener(FormEvents::PRE_SUBMIT, function (FormEvent $event) use (&$submitted_data) {
$submitted_data = $event->getData();
});