我从JSON源读取数据,我获得了空白页错误。
我犯了一个错误。
我只想获得类别bettypeid = 3。
你能帮忙吗?
<?php
error_reporting(1);
header("Content-type: text/xml; charset=utf-8");
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_URL => "https://www.misli.com/scripts/BetList.aspx?action=get&BetTypeId&3",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_TIMEOUT => 30,
CURLOPT_SSL_VERIFYPEER => false,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
//CURLOPT_CUSTOMREQUEST => "GET",
CURLOPT_HTTPHEADER => array(
"accept: application/json",
),
));
$ok = curl_exec($curl);
$err = curl_error($curl);
curl_close($curl);
if ($err) {
echo "cURL Error #:" . $err;
} else {
echo "<Maclar>";
if($ok->BetTypeId=="3")
{
$tarih = $ok->CloseDate;
$ulke = $ok->CountryName;
echo '<ulke="'.$ulke.'" tarih="'.$tarih.'" />';
}
echo "</Maclar>";
}
?>
您要获取数据的目标站点将检查浏览器代理。
添加代理并解决了Scuzzy指出的问题,然后您的代码将起作用。
您可以参考以下代码。请注意,您的XML格式可能存在错误,这将导致浏览器不正常显示响应数据。但是我确实得到了响应<Maclar><ulke="Şampiyonlar Ligi" tarih="2018-02-13T22:45:00" /></Maclar>
代码:
<?php
error_reporting(1);
header("Content-type: text/xml; charset=utf-8");
$agent= 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.84 Safari/537.36';
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_URL => "https://www.misli.com/scripts/BetList.aspx?action=get&BetTypeId&3",
CURLOPT_RETURNTRANSFER => true,
CURLOPT_ENCODING => "",
CURLOPT_TIMEOUT => 30,
CURLOPT_SSL_VERIFYPEER => false,
CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_USERAGENT=>$agent,
CURLOPT_HTTPHEADER => "accept: application/json"
));
$ok = curl_exec($curl);
//echo $ok;
$ok = json_decode($ok);
$err = curl_error($curl);
curl_close($curl);
if ($err) {
echo "cURL Error #:" . $err;
}
else {
echo "<Maclar>";
if($ok[0]->BetTypeId=="3")
{
$tarih = $ok[0]->CloseDate;
$ulke = $ok[0]->CountryName;
echo '<ulke="'.$ulke.'" tarih="'.$tarih.'" />';
}
echo "</Maclar>";
}
?>
希望它有帮助。