您可以帮助我解析以下XML文件吗?
<?xml version="1.0" encoding="UTF-8"?>
<dataset xmlns="http:/foo.com">
<date>2017-10-25T09:13:54+02:00</date>
<element>
<id>1</id>
<name>Stuart</name>
<age>34</age>
<regdate><date>2017-10-25T09:13:54+02:00</date></regdate>
</element>
<element>
<id>2</id>
<name>Lora</name>
<age>12</age>
<regdate><date>2017-10-25T09:13:54+02:00</date></regdate>
</element>
<element>
<id>3</id>
<name>Ben</name>
<age>50</age>
<regdate><date>2017-10-25T09:13:54+02:00</date></regdate>
</element>
</dataset >
我试图创建这样的pojo:
@Getter
@Setter
@JacksonXmlRootElement(localName = "element")
public class ElementXML {
@JacksonXmlProperty(localName = "id")
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "age")
private Long age;
@JacksonXmlProperty(localName = "regdate")
private LocalDateTime regdate;
}
和我使用的解析机制在这里:
XMLInputFactory f = XMLInputFactory.newFactory();
File inputFile = new File("some path");
XMLStreamReader sr = f.createXMLStreamReader(new FileInputStream(inputFile));
ObjectMapper xmlMapper = new XmlMapper();
我之所以被卡住,是因为我不知道如何将元素标签放入我创建的pojo element xml的列表中。您知道如何解决吗?
编辑通过答案进行编辑后的跟踪:
com.fasterxml.jackson.databind.JsonMappingException: Expected END_ELEMENT, got event of type 1 (through reference chain: com.xml.Dataset["element"]->java.lang.Object[][1])
at com.fasterxml.jackson.databind.JsonMappingException.wrapWithPath(JsonMappingException.java:394)
at com.fasterxml.jackson.databind.JsonMappingException.wrapWithPath(JsonMappingException.java:365)
at com.fasterxml.jackson.databind.deser.std.ObjectArrayDeserializer.deserialize(ObjectArrayDeserializer.java:206)
at com.fasterxml.jackson.databind.deser.std.ObjectArrayDeserializer.deserialize(ObjectArrayDeserializer.java:21)
at com.fasterxml.jackson.databind.deser.impl.MethodProperty.deserializeAndSet(MethodProperty.java:127)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:288)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.dataformat.xml.deser.WrapperHandlingDeserializer.deserialize(WrapperHandlingDeserializer.java:113)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4013)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2902)
at com.xml.data.ParseXmlTest.test(ParseXmlTest.java:62)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at org.springframework.test.context.junit4.statements.RunBeforeTestExecutionCallbacks.evaluate(RunBeforeTestExecutionCallbacks.java:74)
at org.springframework.test.context.junit4.statements.RunAfterTestExecutionCallbacks.evaluate(RunAfterTestExecutionCallbacks.java:84)
at org.springframework.test.context.junit4.statements.RunBeforeTestMethodCallbacks.evaluate(RunBeforeTestMethodCallbacks.java:75)
at org.springframework.test.context.junit4.statements.RunAfterTestMethodCallbacks.evaluate(RunAfterTestMethodCallbacks.java:86)
at org.springframework.test.context.junit4.statements.SpringRepeat.evaluate(SpringRepeat.java:84)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:251)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:97)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:70)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:190)
at org.junit.runner.JUnitCore.run(JUnitCore.java:137)
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:68)
at com.intellij.rt.execution.junit.IdeaTestRunner$Repeater.startRunnerWithArgs(IdeaTestRunner.java:47)
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:242)
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:70)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.CommandLineWrapper.main(CommandLineWrapper.java:67)
Caused by: java.io.IOException: Expected END_ELEMENT, got event of type 1
at com.fasterxml.jackson.dataformat.xml.deser.XmlTokenStream.skipEndElement(XmlTokenStream.java:190)
at com.fasterxml.jackson.dataformat.xml.deser.FromXmlParser.nextToken(FromXmlParser.java:584)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:283)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.databind.deser.std.ObjectArrayDeserializer.deserialize(ObjectArrayDeserializer.java:195)
... 43 more
您的问题有些棘手,因为您需要解决一些问题。让我们开始一个一个一个。
1。该型号不适合XML
有效载荷。
首先,您需要创建一个适合您payload
的模型。它不取决于格式,因为对于JSON
和XML
,它几乎相同。为此,我建议总是从序列化过程开始。在Java
中构建模型并尝试序列化要容易得多。如果看起来与预期更新模型所需的预期相同。您迭代这些步骤:update
和serialise
,直到找到有效的模型为止。之后,您可以在没有任何问题的情况下对给定的payload
进行挑选。
2。杰克逊注释。
即使如此,Jackson
的注释也很棒,也不是没有原因的。如果POJO
属性与XML
中的节点名称相同,则无需添加JacksonXmlProperty
注释。当POJO
和payload
中的名称不同时,您必须添加它。在其他情况下,这使POJO
结构过于复杂。我们应该使它尽可能简单。您需要使用一个棘手的注释:JacksonXmlElementWrapper
。当我们有节点收集时,它被使用了。
在这两个简单的段落之后,让我们对您的案件进行认可。我们需要扩展您的POJO
结构,它应该看起来像以下内容:
class Dataset {
private LocalDateTime date;
@JacksonXmlProperty(localName = "element")
@JacksonXmlElementWrapper(useWrapping = false)
private List<Element> elements;
public LocalDateTime getDate() {
return date;
}
public void setDate(LocalDateTime date) {
this.date = date;
}
public List<Element> getElements() {
return elements;
}
public void setElements(List<Element> element) {
this.elements = element;
}
@Override
public String toString() {
return "Dataset{" +
"date=" + date +
", element=" + elements +
'}';
}
}
class Element {
private Long id;
private String name;
private Long age;
private RegDate regdate;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Long getAge() {
return age;
}
public void setAge(Long age) {
this.age = age;
}
public RegDate getRegdate() {
return regdate;
}
public void setRegdate(RegDate regdate) {
this.regdate = regdate;
}
@Override
public String toString() {
return "ElementXML{" +
"id=" + id +
", name='" + name + ''' +
", age=" + age +
", regdate=" + regdate.getDate() +
'}';
}
}
class RegDate {
private LocalDateTime date;
public RegDate() {
this(null);
}
public RegDate(LocalDateTime date) {
this.date = date;
}
public LocalDateTime getDate() {
return date;
}
public void setDate(LocalDateTime date) {
this.date = date;
}
@Override
public String toString() {
return "RegDate{" +
"date=" + date +
'}';
}
}
一个示例用法:
import com.fasterxml.jackson.databind.SerializationFeature;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;
import com.fasterxml.jackson.datatype.jsr310.deser.LocalDateTimeDeserializer;
import java.io.File;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.util.List;
public class XmlMapperApp {
public static void main(String[] args) throws Exception {
File jsonFile = new File("./resource/test.xml").getAbsoluteFile();
JavaTimeModule module = new JavaTimeModule();
module.addDeserializer(LocalDateTime.class, new LocalDateTimeDeserializer(DateTimeFormatter.ISO_DATE_TIME));
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.registerModule(module);
xmlMapper.enable(SerializationFeature.INDENT_OUTPUT);
Dataset dataset = xmlMapper.readValue(jsonFile, Dataset.class);
dataset.getElements().forEach(System.out::println);
}
}
上面的代码打印:
ElementXML{id=1, name='Stuart', age=34, regdate=2017-10-25T09:13:54}
ElementXML{id=2, name='Lora', age=12, regdate=2017-10-25T09:13:54}
ElementXML{id=3, name='Ben', age=50, regdate=2017-10-25T09:13:54}
上述代码的两个额外评论。当您使用java.time.*
类并且Jackson
工作时,可以从注册来自Jackson-Datatype-JSR310模块的JavaTimeModule
开始。由于我们正在使用它,因此我们可以指示使用ISO_DATE_TIME
格式用于LocalDateTime
类。在其他答案中,您可以找到使用JsonFormat
注释的示例。这也是很好的解决方案,但是当所有日期具有相同格式的定义更容易时。
有关更多信息,请阅读:
- 如何更新RESTTEMPLATE以正确映射Java日期?
- 与杰克逊JSR310模块的localdatetime
- 找不到伪影杰克逊模型 - 贾瓦8:jar
不可能仅通过一个POJO类对给定的XML内容进行建模。您将需要几个POJO类来正确建模XML内容。
用于建模<dataset>
root元素您需要类,我们称其为Dataset
。
@Getter
@Setter
@JacksonXmlRootElement(localName = "dataset")
public class Dataset {
@JacksonXmlProperty(localName = "date")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ssXXX")
private LocalDateTime date;
@JacksonXmlProperty(localName = "element")
@JacksonXmlElementWrapper(useWrapping = false)
private List<ElementXML> elements;
}
在上面的代码中注意
-
date
属性用@JsonFormat
注释以指定使用日期时间格式 -
elements
用@JacksonXmlElementWrapper(useWrapping = false)
注释告诉解析器不要期望<element>
的顺序额外包装
接下来,您需要一个用于建模<element>...</element>
之间的XML内容的类非常喜欢您的ElementXML
类。
@Getter
@Setter
public class ElementXML {
@JacksonXmlProperty(localName = "id")
private Long id;
@JacksonXmlProperty(localName = "name")
private String name;
@JacksonXmlProperty(localName = "age")
private Long age;
@JacksonXmlProperty(localName = "regdate")
private RegDate regdate;
}
在上面的代码中注意,您需要对regdate
属性进行建模更精致。因为XML内容看起来不像<regdate>2017-10-25T09:13:54+02:00</regdate>
您不能简单地将其声明为LocalDate regdate
。相反,XML看起来像<regdate><date>2017-10-25T09:13:54+02:00</date></regdate>
。因此,您需要用另一个类对其进行建模(我们称其为RegDate
)
最后,这是用于建模XML内容的RegDate
类在<regdate>...</regdate>
之间。
@Getter
@Setter
public class RegDate {
@JacksonXmlProperty(localName = "date")
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd'T'HH:mm:ssXXX")
private LocalDateTime date;
}
再次注意使用@JsonFormat
指定日期时间格式。
使用上面的类,您可以像这样解析xml
File inputFile = new File("some path");
ObjectMapper xmlMapper = new XmlMapper();
xmlMapper.registerModule(new JavaTimeModule());
Dataset dataset = xmlMapper.readValue(inputFile, Dataset.class);