假设我在下表中。如果我的联接表与日期和货币不匹配,如何获取最新的先前值?在空 DKK 值上,我希望它拾取 3。请注意,日期不是每天都存在,因为我不在周末加载表。
Select
PositionDate,
Currency,
T2.Value,
isnull(t2.value, ? )
From t1
left join t2
on t1.currency = t2.Currency
and t1.PositionDate = t2.PositionDate
.
PositionDate Currency Value
2017-04-11 SEK 1
2017-04-11 DKK NULL
2017-04-11 EUR 7
2017-04-10 SEK 4
2017-04-10 DKK 3
2017-04-10 EUR 5
2017-04-07 SEK 4
2017-04-07 DKK 3
2017-04-07 EUR 5
.
我认为这将适用于您的情况:
SELECT
t1.PositionDate,
t1.Currency,
COALESCE(t1.Value,t2.value) AS Value
FROM t1
LEFT join (SELECT MAX(PositionDate) AS PositionDate,Currency FROM t2 WHERE PositionDate < t1.PositionDate GROUP BY Currency) tjoin
LEFT join t2 on tjoin.currency = t2.Currency and tjoin.PositionDate = t2.PositionDate
您可以使用 CTE 和案例条件来实现它。
With cte as
(
Select
PositionDate,
Currency,
T2.Value,
From t1
left join t2
on t1.currency = t2.Currency
and t1.PositionDate = t2.PositionDate
and t1.PositionDate = t2.PositionDate
)
select PositionDate, Currency, Value,
CASE WHEN ISNULL(value,'')='' THEN
(Select top 1 from cte cin where cin.currency=cout.currency order by CONVERT(Date,PositionDate) desc)
ELSE
Value
END as Value2
From cte cout