PHP:如何比较嵌套关联数组中的值?

Question

我正在尝试如何实现这一目标...

我有一个类似的东西：

$contributors = array(
[0] => array(
[name] => 'John',
[role] => 'author',
),
[1] => array(
[name] => 'Gail',
[role] => 'author',
),
[2] => array(
[name] => 'Beth',
[role] => 'illustrator',
),
)

我正在尝试使用此信息来构建详细的署名，例如：

由约翰和盖尔撰写。由贝丝设计。

我需要将每个role与上一个和下一个进行比较，以便：

1. 在每个role的第一个实例之前使用标签
2. 用逗号分隔同一role的多个实例
3. 在每个role的最后一个实例之前使用"and"而不是逗号

我不是PHP专家，所以我很难弄清楚如何处理这个问题！我有一个功能可以根据role输出正确的标签，但我似乎无法弄清楚比较。我考虑过foreach和while循环，但似乎都不能胜任这项工作。我从未使用过for循环，所以我不知道它是否适用。

一些额外的背景：

• 我正在使用WordPress和高级自定义字段插件。
• $contributors是 ACF 中继器字段的值，其中name和role是子字段。(我简化了名称以使事情变得更容易。

Answer 1

您可以按角色对数组进行分组，并使用array_pop删除元素。implode剩余的数组元素，只需附加弹出的值。

$contributors = array(
array(
"name" => 'John',
"role" => 'author',
),
array(
"name" => 'Gail',
"role" => 'author',
),
array(
"name" => 'Jose',
"role" => 'author',
),
array(
"name" => 'Thomas',
"role" => 'author',
),
array(
"name" => 'Beth',
"role" => 'illustrator',
),
array(
"name" => 'Mary',
"role" => 'producer',
),
array(
"name" => 'Criss',
"role" => 'producer',
),
);
//Grouped the names according to role
$grouped = array_reduce($contributors, function($c, $v) {
if ( !isset( $c[ $v['role'] ] ) ) $c[ $v['role'] ] = array();
$c[ $v['role'] ][] = $v['name'];
return $c;
}, array());

//Construct final Array
$final = array();
foreach( $grouped as $key => $group ) {
$last = array_pop( $group );
if ( count( $group ) == 0 ) $final[ $key ] = $last; /* One one name on the role, no need to do anything*/
else $final[ $key ] = implode( ", ", $group ) . " and " . $last;
}
echo "<pre>";
print_r( $final );
echo "</pre>";

这将导致：

Array
(
[author] => John, Gail, Jose and Thomas
[illustrator] => Beth
[producer] => Mary and Criss
)

您现在可以将其用作

echo 'Written by ' . $final["author"] . '. Designed by ' . $final["illustrator"] . '. Produced by ' . $final["producer"];

并将导致：

由约翰，盖尔，何塞和托马斯撰写。由贝丝设计。出品方 玛丽和克里斯

Answer 2

你可以这样尝试——

$contributors = array(
array(
'name' => 'John',
'role' => 'author',
),
array(
'name' => 'Gail',
'role' => 'author',
),
array(
'name' => 'Ali',
'role' => 'author',
),
array(
'name' => 'Beth',
'role' => 'illustrator',
)
);
#This function prepare array to expected String
function PrepareArray($data){
$combined = '';
if (count($data)>1) {
$last       = array_slice($data, -1);
$first      = join(', ', array_slice($data, 0, -1));
$both       = array_filter(array_merge(array($first), $last), 'strlen');
$combined   = join(' and ', $both);
}else{
$combined = implode('', $data);
}
return $combined;
}
$authors    = array();
$designers  = array();
foreach ($contributors as $key => $value) {
if ($value['role']=='author') {
$authors[]      = $value['name'];        #Keep Authors name in Array
}else if ($value['role']=='illustrator') {
$designers[]    = $value['name'];            #Keep Designers name in Array
}
}
$authors    = PrepareArray($authors);
$designers  = PrepareArray($designers);
echo "Written by {$authors}. Designed by {$designers}.";

输出：

由约翰、盖尔和阿里撰写。由贝丝设计。

Answer 3

尝试以下代码：

<?php
$contributors = array(
0 => array(
'name' => 'John',
'role' => 'author',
),
1 => array(
'name' => 'Gail',
'role' => 'author',
),
2 => array(
'name' => 'Beth',
'role' => 'illustrator',
),
3 => array(
'name' => 'Albert',
'role' => 'author',
),
);

$labels = ['author'=>'Written by', 'illustrator'=>'Designed by', 'producer'=>'Produced by'];
$new_contributors = [];
foreach($contributors as $cont){
$new_contributors[$cont['role']][] = $cont['name'];
}
$str = '';
foreach($labels as $role=>$label){
if(isset($new_contributors[$role]) && is_array($new_contributors[$role])){
$str .= ' '.$label.' ';
foreach($new_contributors[$role] as $key=>$new_contributor){
$count = count($new_contributors[$role]);
if(($count - $key) == 1 ){
$str .= ' and ';
$str .= $new_contributor;
}else if(($count - $key) == 2){
$str .= $new_contributor;
}else{
$str .= $new_contributor.', ';
}
}
}
}
echo $str;