如何迭代 JSONObject 并按已知的值找到 id，例如我想获取值的 id "ТС-41"我该怎么做？

Question

{" 0"："，" 54049"："op。MZ-61A"，" 100606"：" KM-41"，" 100609"：" MT-41"，" 100612"：" EM-41"，" 100684"：" HK-51"，" 100685"：" EM-51"，" 100687"：" KM-51"，" 100688"：" MT-51"，" 100718"：" HK-51/1"，" 100719"：" HK-51/2"，" 100748"：" TS-61"，" 100749"：" TS-61/1"，" 100750"：" TS-61/2"，" 100754"：" EM-61"，" 100758"：" IM-61/1MB"，" 100759"：" IM-61/2GT"，" 100760"：" MB-61"，" 100767"：" TS-51"，" 100770"：" TS-41"，" 100777"：" TS.M-61"，" 100778"：" MT.M-61"，" 100779"：" EM.M-61"，" 100780"：" TM.M-61"，" 100781"：" TM.M-62"，" 100782"：" GM.M-61"，" 100783"：" vi.m-61"，" 100786"：" KHM.M-61"}

Answer 1

您需要在jsonobject键上迭代并比较值直至匹配。

final String knownValue = "TC-41";
final Iterator<String> iterable = jsonObject.keys();
while (iterable.hasNext()) {
    String key = iterable.next();
    if (jsonObject.getString(key).equals(knownValue)) {
        // key has the value you are looking for
       return;
    }
}

Answer 2

使用JSON类进行解析

JSONObject mainObject = new JSONObject(Your_Sring_data);
String id = mainObject .getString("100770");
 //here in this **id** string you can get value for **"TC-41"**