以下是我的测试代码。我的问题是在第二页中我无法引用AndroidFunction2。我正在带有Android 7的Nexus 4.4上对此进行测试。但是在带有Android 4.0的sumsang i9100上也可以。 是我做错了什么,还是有安卓的错误?
主活动
public class MainActivity extends Activity {
WebView mWebView1;
WebView mWebView2;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final FrameLayout mainFrame = (FrameLayout) this.findViewById(R.id.mainFrame);
mWebView1 = new WebView(this);
mWebView1.getSettings().setJavaScriptEnabled(true);
mWebView1.getSettings().setSupportMultipleWindows(true);
mWebView1.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
return false;
}
});
mWebView1.setWebChromeClient(new WebChromeClient() {
@Override
public boolean onCreateWindow(WebView view, boolean isDialog,
boolean isUserGesture, Message resultMsg) {
mWebView2 = new WebView(MainActivity.this);
mWebView2.getSettings().setJavaScriptEnabled(true);
mWebView2.getSettings().setSupportMultipleWindows(true);
mWebView2.setWebChromeClient(new WebChromeClient() {
@Override
public void onConsoleMessage(String message, int lineNumber, String sourceID) {
Log.d("WebView", "Line: " + lineNumber + ", " + message);
}
});
mWebView2.addJavascriptInterface(new Object() {
@JavascriptInterface
public void hello2() {
}
}, "AndroidFunction2");
(( WebViewTransport )resultMsg.obj).setWebView(mWebView2);
resultMsg.sendToTarget();
mainFrame.addView(mWebView2);
return true;
}
});
mWebView1.addJavascriptInterface(new Object() {
@JavascriptInterface
public void hello1() {
}
}, "AndroidFunction1");
mWebView1.loadUrl("file:///sdcard/test_1.html");
mainFrame.addView(mWebView1);
}
}
而两个网页,
test_1.html:
<html>
<body>
<a href="test_2.html" target="_blank">goto test 2</a>
<div><a href="javascript:alert(typeof AndroidFunction1);"> alert(typeof AndroidFunction1);</a> </div>
<div><a href="javascript:alert(typeof window.AndroidFunction1);"> alert(typeof window.AndroidFunction1);</a> </div>
</body>
</html>
test_2.html
<html>
<body>
<div><a href="javascript:alert(AndroidFunction2);"> alert(AndroidFunction2);</a> </div>
<div><a href="javascript:alert(typeof window.AndroidFunction2);"> alert(typeof window.AndroidFunction2);</a> </div>
</body>
</html>
即使我也有同样的问题,在再次浏览文档后,我发现如果您已将targetSdkVersion
设置为 17 or higher
,则必须将@JavascriptInterface
注释添加到您希望可用于 JavaScript 的任何方法中(该方法也必须是公共的)。
如果您不提供注释,则在 Android 4.2 或更高版本上运行时,您的网页无法访问该方法。
以下示例(取自 http://developer.android.com/guide/webapps/webview.html)表明您可以在 Android 应用程序中包含以下类:
public class WebAppInterface {
Context mContext;
/** Instantiate the interface and set the context */
WebAppInterface(Context c) {
mContext = c;
}
@JavascriptInterface // must be added for API 17 or higher
public void showToast(String toast) {
Toast.makeText(mContext, toast, Toast.LENGTH_SHORT).show();
}
}
并绑定为
WebView webView = (WebView) findViewById(R.id.webview);
webView.addJavascriptInterface(new WebAppInterface(this), "Android");
然后从 Web 视图内的 HTML 调用
<input type="button" value="Say hello" onClick="showAndroidToast('Hello Android!')" />
<script type="text/javascript">
function showAndroidToast(toast) {
Android.showToast(toast);
}
</script>