如何将存储过程的结果映射到 spring-boot/hibernate 中的实体

Question

我有一个实体类，如下所示

注意：校验号是唯一的。

package tz.go.ega.biometic.entity;

import java.io.Serializable;
import java.time.LocalDateTime;
import java.util.List;
import javax.persistence.*;
import javax.validation.constraints.NotEmpty;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Pattern;
import lombok.ToString;
import org.hibernate.annotations.NaturalId;
import org.hibernate.validator.constraints.SafeHtml;
import org.springframework.data.annotation.Transient;
import org.springframework.format.annotation.DateTimeFormat;
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.NoArgsConstructor;
@Entity
@Table(name = "employee", uniqueConstraints = {
@UniqueConstraint(columnNames = {"check_number"})
})
@Data
@AllArgsConstructor
@ToString
@NoArgsConstructor
public class Employee implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Long id;
@Basic(optional = true)
//@NotEmpty(message = "Please enter first name")
@Column(name = "first_name")
private String firstName;
@Basic(optional = true)
//@NotEmpty(message = "Please enter middle name")
@Column(name = "middle_name")
private String middleName;
@Basic(optional = true)
//@NotEmpty(message = "Please enter last name")
@Column(name = "last_name")
private String lastName;
private String status;
@Basic(optional = true)
// @Pattern(regexp ="^[a-zA-Z0-9_]*$",message = "{field.validation.voteCode}")
// @SafeHtml(message = "{field.validation.voteCode}")
@Column(name = "vote_code", length = 50)
private String voteCode;
@NaturalId
@Basic(optional = true)
//@NotNull(message = "Please enter check number")
@Column(name = "check_number")
private long checkNumber;
private Boolean isActive = true;

@Basic(optional = false)
@Column(name = "created_at", updatable = false)
@DateTimeFormat(pattern = "yyyy-MM-dd hh:mm:ss")
private LocalDateTime createdAt = LocalDateTime.now();
@Column(name = "updated_at")
@DateTimeFormat(pattern = "yyyy-MM-dd hh:mm:ss")
private LocalDateTime updatedAt = LocalDateTime.now();

@Column(name = "email")
private  String email;
}

然后，我有一个存储过程，用于计算每个员工的工作时间，然后返回如下所示的结果。

+--------------+-------+
| checkNumber  | Time  |
+--------------+-------+
| 1122334455   | 29893 |
| 1234567890   | 15427 |
| 2233445566   | 19745 |
| 6655443322   | 12578 |
+--------------+-------+

我试图实现的是，将存储过程的结果(如上所示(映射到一个实体(我们称之为 EmployeeWorkHours (，然后使用 checkNumber 在此实体和 Employee 实体之间创建关系。

我希望 EmployeeWorkHours 对象能够像在正常的休眠关系中一样直接引用它的员工。

我该怎么做，任何帮助将不胜感激。谢谢。

Answer 1

在员工工作时间实体上，您需要与员工实体建立一对一关系

@OneToOne(optional = false, fetch = FetchType.EAGER)
@JoinColumn(name = "checkNumber", unique = true, nullable = false)
private Employee employee;

在您的存储库中，您可以编写如下 sql 查询：

@Query(value = "{CALL yourStoredProcedure (:var1, :var2, ..., :varn)}", nativeQuery = true)
int getWorkHours(@Param("var1") String var1, @Param("var2") String var2,...,
@Param("varn") String varn);

然后在您的服务层中，您只需调用此方法执行您想要的其他操作并持久化它。 希望对你有帮助