如何使构建器在时髦而不是与嵌套的if一起使用

Question

我必须构建和id，这取决于不同的参数。如果其中一些不是空的，y 必须根据参数将这些值附加一些联合符号(如"~"(或一些前缀。

这是我使用嵌套执行的实现，如果：

def buildUID( def sportId, def leagueId, def groupId, def eventId, def teamId, def competitionId )
{
def delimiter = "~"
def returnString = ""
sportId = sportId + ''
leagueId = leagueId + ''
groupId = leagueId + ''
teamId = teamId + ''
eventId = eventId + ''
competitionId = competitionId + ''
if ( this.commonPresenter.isNotNull( sportId ) )
{
returnString = "s:" + sportId
if ( this.commonPresenter.isNotNull( leagueId ) )
{
if ( this.commonPresenter.isNull( teamId ) )
{
if ( this.commonPresenter.isNull( groupId ) )
{
if ( this.commonPresenter.isNotNull( eventId ) )
{
returnString = returnString + delimiter + "l:" + leagueId + delimiter + "e:" + eventId
}
else if ( this.commonPresenter.isNotNull( competitionId ) )
{
returnString = returnString + delimiter + "l:" + leagueId + delimiter + "c:" + competitionId
}
else
{
returnString = returnString + delimiter + "l:" + leagueId
}
}
else
{
returnString = returnString + delimiter + "l:" + leagueId + delimiter + "g:" + groupId
}
}
else if ( sportId == "600" )
{
returnString = returnString + delimiter + "t:" + teamId
}
else
{
returnString = returnString + delimiter + "l:" + leagueId + delimiter + "t:" + teamId
}
}
else if ( ( this.commonPresenter.isNull( leagueId ) ) && sportId == "600" && this.commonPresenter.isNotNull( teamId ) )
{
returnString = returnString + delimiter + "t:" + teamId
}
}
return returnString + ''
}

谢谢。

Answer 1

只是一个想法：使用map和函数来处理集合

def ret = [
sportId:11,
leagueId:22, 
groupId:null, 
eventId:44, 
teamId:'z', 
competitionId:66
].findAll{it.value!=null}.collect{it.key[0]+':'+it.value}.join('~')

返回

s:11~l:22~e:44~t:z~c:66