#include <iostream>
using namespace std;
void main(int argc, char* argv[])
{
int conversion, hash;
cout << "Select one." << endl;
cout << "0: Radix Method 32" << endl;
cout << "1: Radix Method 64" << endl;
cout << "2: SumUp" << endl;
cin >> conversion;
cout << endl << "Select one." << endl;
cout << "0: Division" << endl;
cout << "1: Multiplication" << endl;
cin >> hash;
cout << "Conversion: " + conversion << endl;
cout << "hash: " + hash << endl;
}
就这么简单,我得到了疯狂的输出。 我觉得这是显而易见的,但我太累了,看不到它。 我在变量中输入的数字是从下一个输出字符串中删除的字符数。 前任:
Select one.
0: Radix Method 32
1: Radix Method 64
2: SumUp
1
Select one.
0: Division
1: Multiplication
2
onversion:
sh:
Press any key to continue . . .
Select one.
0: Radix Method 32
1: Radix Method 64
2: SumUp
5
Select one.
0: Division
1: Multiplication
1
rsion:
ash:
Press any key to continue . . .
我是疯了还是这毫无意义?我用错cin
了吗? 我已经几个月没有使用C++了,但我看不出有什么问题。
cout << "Conversion: " + conversion
表示从数组头部之后的conversion
元素打印。
您可能希望这样做(将+
更改为<<
):
cout << "Conversion: " << conversion << endl;
cout << "hash: " << hash << endl;