将 json 数组元素替换为另一个数组 c# 的元素

Question

我有两个json字符串。

string days = "['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']";
string data= "[[0,0,0],[2,1,0],[0,2,0],[3,3,0],[0,6,0],[0,7,0],[5,8,0],[0,9,1],[6,10,3],[0,11,5],[0,12,4],[4,13,7],[0,14,1]]";

我想转换 json 数据，以便..

对于所有数组，例如 [0,0,0]

a）如果最后一个值为0，则从数据中删除此数组

b） 将第一个值

替换为第一个值（以天为单位）数组例如..[3,13,7] 变为 ["星期三"，13,7]

我从这个开始..

JArray daysarr = JArray.Parse(days);
JArray myarr = JArray.Parse(data);
foreach (var myobj in myarr)
{
    // what do I do here????
}  

任何帮助都非常感谢。

谢谢

Answer 1

这个解决方案怎么样：

var js = new JavaScriptSerializer();
string days = "['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']";
string data = "[[0,0,0],[2,1,0],[0,2,0],[3,3,0],[0,6,0],[0,7,0],[5,8,0],[0,9,1],[6,10,3],[0,11,5],[0,12,4],[4,13,7],[0,14,1]]";
var Days = js.Deserialize<List<string>>(days);
var Data = js.Deserialize<List<List<int>>>(data);
var answer = js.Serialize(Data.Where(x => x.Last() != 0).ToList().Select(x => {
    var list = new List<object> { Days[x.First()] };
    list.AddRange(x.Skip(1).Select(y => (object)y).ToList());
    return list;
}).ToList());

Answer 2

 string days = "['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']";
        string data = "[[0,0,0],[2,1,0],[0,2,0],[3,3,0],[0,6,0],[0,7,0],[5,8,0],[0,9,1],[6,10,3],[0,11,5],[0,12,4],[4,13,7],[0,14,1]]";
        JArray daysarr = JArray.Parse(days);
        JArray myarr = JArray.Parse(data);
        JArray result = new JArray();

        foreach (var myobj in myarr)
        {
            if (myobj.Last.Value<int>() != 0)
            {
                var t = new object[3];
                t[0] = daysarr[myobj.First.Value<int>()];
                t[1] = myobj[1];
                t[2] = myobj[2];
                result.Add(t);
            }
        }

Answer 3

foreach循环是只读的（你不能修改正在迭代的集合，比如删除项目等）;您可以使用 for 循环代替，在这种情况下，您需要一个可以存储字符串和整数的新容器，例如 List<Tuple<object, int, int>> .

您还需要一个if声明：

JArray daysarr = JArray.Parse(days);
JArray myarr = JArray.Parse(data);
var result = new List<Tuple<object, int, int>>();
foreach(myobj in myarr)
{
    if(myobj[2] != 0)
    {
        var newValue = new Tuple<object, int, int>(daysarr[myobj[0]], myobj[1], myobj[2]);
        result.Add(newValue);
    }
} 

Answer 4

你能试试下面的代码吗：

string days = "['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']";
string data = "[[0,0,0],[2,1,0],[0,2,0],[3,3,0],[0,6,0],[0,7,0],[5,8,0],[0,9,1],[6,10,3],[0,11,5],[0,12,4],[4,13,7],[0,14,1]]";
JArray daysarr = JArray.Parse(days);
JArray myarr = JArray.Parse(data);
// a) If the last value is 0 remove this array from data
// b) Replace the first value with the first value in days array eg ..[3,13,7] becomes ["Wednesday",13,7]
// This result array we used for storing all valid data which follow the two rules as define above comment.
JArray result = new JArray();
foreach (var myobj in myarr)
{
    if (myobj.Count() == 3)
    {
        var firstValue = Convert.ToInt32(myobj[0]);
        var secondValue = Convert.ToInt32(myobj[1]);
        var thirdValue = Convert.ToInt32(myobj[2]);
        // Here we check last value of current array
        if (thirdValue != 0)
        {
            string day = Convert.ToString(daysarr[firstValue]);
            myobj[0] = day;
            result.Add(myobj);
        }
    }
}