我正在使用braintree paypal结帐函数,我找到了jQuery代码,我需要将braintree sandbox auth键放在jquery varible中,我在braintree中创建了帐户,我尝试了所有该代码,但是在JQuery Console日志中它说验证失败了,有人可以帮助我在哪里可以找到该代码?这是我的相同代码
<!DOCTYPE html>
<head>
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1">
<script src="https://www.paypalobjects.com/api/checkout.js"></script>
<script src="https://js.braintreegateway.com/web/3.11.0/js/client.min.js"></script>
<script src="https://js.braintreegateway.com/web/3.11.0/js/paypal-checkout.min.js"></script>
</head>
<body>
<div id="paypal-button-container"></div>
<script>
var BRAINTREE_SANDBOX_AUTH = '38mqtdwp4nth5tbk';
// Render the PayPal button
paypal.Button.render({
// Pass in the Braintree SDK
braintree: braintree,
// Pass in your Braintree authorization key
client: {
sandbox: BRAINTREE_SANDBOX_AUTH,
production: '<insert production auth key>'
},
// Set your environment
env: 'sandbox', // sandbox | production
// Wait for the PayPal button to be clicked
payment: function(data, actions) {
// Make a call to create the payment
return actions.payment.create({
payment: {
transactions: [
{
amount: { total: '1', currency: 'USD' }
}
]
}
});
},
// Wait for the payment to be authorized by the customer
onAuthorize: function(data, actions) {
// Call your server with data.nonce to finalize the payment
console.log('Braintree nonce:', data.nonce);
// Get the payment and buyer details
return actions.payment.get().then(function(payment) {
console.log('Payment details:', payment);
});
}
}, '#paypal-button-container');
</script>
</body>
我需要在此变量var BRAINTREE_SANDBOX_AUTH = '38mqtdwp4nth5tbk';
中放置代码,任何人可以帮助我解决此问题吗?
全面披露:我在braintree工作。如果您还有其他疑问,请随时联系support@braintroepayments.com。
看起来您将BRAINTREE_SANDBOX_AUTH
变量设置为商户ID,而不是客户端令牌。为了启动Braintree结帐,您将需要生成,然后传递client_token
。
您在服务器上生成client_token
,然后将其传递到客户端呼叫中:braintree.client.create()
。
如果成功,braintree.client.create()
将返回一个客户端实例,您可以使用braintree.paypalCheckout.create()
来创建PayPal Checkout组件。
在PaypalCheckout组件中,您可以使用paypal.Button.render()
配置PayPal按钮。