大家好。我有密码。根据我的理解,clickd2应该得到id"Third",因为它正在寻找孩子。但不知何故,它总是得到id"第一"。我怎么得到"第三"?
<!DOCTYPE html>
<html>
<body>
<div class="menu" id="First">
<button id="Second">eee</button>
<button id="Third">yyy</button>
</div>
<div class="holder"></div>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).on('click', '.menu', function(e) {
var clicked = e.target.id || this.id;
var clicked2 = e.target.children.id || this.id;
var y = clicked2.replace(/D/g, '');
var x = clicked.replace(/D/g, '');
var w = 0;
$('.holder') .append('<BR>'+clicked+'<BR>'+clicked2);
});
</script>
</body>
</html>
添加此var clicked2 = $(this).children("button").next().attr("id")
它将返回第二个按钮的id。
试试这个
$(document).on('click', '.menu', function(e) {
var clicked = e.target.id || this.id;
var clicked2 = $(this).children("button").next().attr("id") || this.id;
var y = clicked2.replace(/D/g, '');
var x = clicked.replace(/D/g, '');
var w = 0;
$('.holder') .append('<BR>'+clicked+'<BR>'+clicked2);
});
演示
children()返回所有的子元素,所以您需要处理正确的子元素:
var clicked2 = $(this).children().next().attr("id");