从 NSMutableArray 的单词对象中对单词进行干净的 NSString，然后用于搜索

Question

suitsArray 是可变数组，当按钮处于选定状态时添加对象（单词）。

在下面的文章中，我需要使suitsCriteriaString成为一个干净的字符串，只有一个空格将单词与suitsArray分开，这意味着没有逗号或其他符号！（用NSSet什么的？

NSString *suitsCriteriaString = [NSString stringWithFormat:@"%@", suitsArray];
NSString *wineSuitsString = [wine objectForKey:@"Suits"];
NSRange range = [wineSuitsString rangeOfString:suitsCriteriaString options:NSCaseInsensitiveSearch];

然后，如果做得正确，NSRange应该检查suitsCriteriaString中的单词是否存在于wineSuitsString中。然后，应过滤结果以仅包含匹配的单词！

我的搜索功能的代码如下，如果您需要更多信息来完成这项工作，请告诉我。

---

SearchViewController.h

---

#import <UIKit/UIKit.h>
@interface SearchViewController : UIViewController {
@property (nonatomic, strong) NSMutableArray *allObjectsArray;
@property (nonatomic, strong) NSMutableArray *resultObjectsArray;
@property (nonatomic, strong) NSMutableArray *suitsArray;
@property (nonatomic, retain) IBOutlet UISlider *minPrisSlider;
@property (nonatomic, retain) IBOutlet UISlider *maxPrisSlider;
-(IBAction)searchButtonPressed:(id)sender;
@end

---

SearchViewController.m：

---

填充所有对象数组：

- (void)viewDidLoad
{
[super viewDidLoad];
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDirectory = [paths objectAtIndex:0];
NSString *path = [documentsDirectory stringByAppendingPathComponent:@"Wine.plist"];
allObjectsArray = [[NSMutableArray alloc] initWithContentsOfFile:path];
}

---

在suitsArray中添加或删除对象，我有10个类似于这样的按钮：

-(IBAction)lambButtonPressed:(id)sender
{
if (lambButtonSelected == 0) {
    lambButtonSelected = 1;
    [suitsArray addObject:@"lamb"];
} else {
    lambButtonSelected = 0;
    [suitsArray removeObject:@"lamb"];
}
}

---

然后，将对象添加到搜索结果：

-(IBAction)searchButtonPressed:(id)sender{  
resultObjectsArray = [NSMutableArray array];
for(NSDictionary *wine in allObjectsArray)
    {
    //String for price
    NSString *winePrice = [wine objectForKey:@"Price"];        
    /*THIS IS WHERE I'M TRYING TO CHECK IF THE WORDS IN suitsCriteriaString
    ARE EXISTING IN wineSuitsString */
    NSString *suitsCriteriaString = [NSString stringWithFormat:@"%@", suitsArray];
    NSString *wineSuitsString = [wine objectForKey:@"Suits"];
    NSRange range = [wineSuitsString rangeOfString:suitsCriteriaString options:NSCaseInsensitiveSearch];

    //THEN LAST, ADD OBJECTS WITH MATCH OF PRICE CRITERIA AND SUITS CRITERIA TO RESULTS:
    BOOL priceConditionGood = YES;
    if (minPrisSlider.value <= maxPrisSlider.value && (winePrice.floatValue < minPrisSlider.value || winePrice.floatValue > maxPrisSlider.value))
        priceConditionGood = NO;
    if (range.location != NSNotFound && priceConditionGood)
        [resultObjectsArray addObject:wine];
     }
     }
//AND PUSH RESULTS CONTROLLER:
ResultsTableViewController *nextController = [[self storyboard] instantiateViewControllerWithIdentifier:@"ResultsController"];
nextController.objectsArray = [[NSMutableArray alloc]initWithArray:resultObjectsArray];
[self.navigationController pushViewController:nextController animated:YES];
}

Answer 1

"suitsCriteriaString" 不会给你你想要的。迭代"suitsArray"并比较每个单词会容易得多：

NSString *wineSuitsString = [wine objectForKey:@"Suits"];
BOOL foundMatch = true;
for (NSString *suit in suitsArray) {
  NSRange range = [wineSuitsString rangeOfString:suit options:NSCaseInsensitiveSearch];
  if (range.location == NSNotFound) {
    foundMatch = false;
    break;
  }
}

Answer 2

您可以使用 componentsJoinedByString： 方法执行此操作，如下所示：

NSString *suitsCriteriaString = [suitsArray componentsJoinedByString:@" "];
NSString *wineSuitsString = [wine objectForKey:@"Suits"];
NSRange range = [wineSuitsString rangeOfString:suitsCriteriaString options:NSCaseInsensitiveSearch];