python序列化rest和graphql相同

Question

我一直在玩graphql(graphene(，编写一个基于python/falcon的小应用程序，该应用程序返回帖子列表，包括REST＆amp;GraphQl：

from falcon import API, json
import graphene
def get_all_posts():
    posts = [
        {
            'content': (
                'Hello, '
                "World..."
            ),
            'author': 'Unknown author'
        }
    ]
    return posts

class Query(graphene.ObjectType):
    posts = graphene.String()
    def resolve_posts(self, info):
        return get_all_posts()

schema = graphene.Schema(query=Query)
class PostsResource:
    def on_get(self, req, resp):
        posts = get_all_posts()
        resp.media = {'posts': json.dumps(posts)}

class GraphQLResource:
    def on_get(self, req, resp):
        query = req.params['query']
        result = schema.execute(query)
        resp.media = result.data

api = API()
api.add_route('/graphql', GraphQLResource())
api.add_route('/posts', PostsResource())

查询 graphQl (localhost/graphql？query = query％20posts％20 {％20posts％20}(

态

使用休息终点(localhost/post(

{" posts"：" [{{" content "：" Hello，world ... "，"作者"："未知作者"}]"}

我不确定这是否重要，但是我想知道为什么序列序列不同？

尝试实现这一目标是有意义的吗？

任何帮助将不胜感激！谢谢！

• p.s如果我不倾倒(json.dumps()(我得到的剩余终点的结果：

{" posts"：[{" content"："你好，世界..."，"作者"："未知作者"}]}

Answer 1

看起来它将整个帖子列表序列化为单字符串(posts = graphene.String()(。我对graphene不太熟悉，但您必须创建嵌套模式 - 类似的架构：

class Post(graphene.ObjectType):
    content = graphene.String()
    author = graphene.String()
class Query(graphene.ObjectType):
    # or Field instead of List, I'm not sure about that.
    posts = graphene.List(Post)

我希望它能帮助您继续解决问题