将 Zip 内容读取到字符串中时"ZipException - unexpected end of file when reading short buff"

Question

我正在使用zip4j库来压缩和解压缩文件(特别是xml(。对于传入的String，我需要将String的内容写入xml文件，然后将该文件压缩到 zip 文件中，然后再将 zip 文件的byte[]内容传输到apache camel正文对象中。压缩部分工作正常，这里没有问题。

当我尝试将消息读回我的应用程序时，我收到以下错误 -

net.lingala.zip4j.exception.ZipException: unexpected end of file when reading short buff
at net.lingala.zip4j.core.HeaderReader.readIntoBuff(HeaderReader.java:1094)
at net.lingala.zip4j.core.HeaderReader.readCentralDirectory(HeaderReader.java:221)
at net.lingala.zip4j.core.HeaderReader.readAllHeaders(HeaderReader.java:94)
at net.lingala.zip4j.core.ZipFile.readZipInfo(ZipFile.java:425)
at net.lingala.zip4j.core.ZipFile.getFileHeaders(ZipFile.java:688)
at ZipUtil.unzipFile(ZipUtil.java:230)
at ZipUtil.unzipFile(ZipUtil.java:218)

我正在做的本质上是——

1. 使用 'exchange.getIn((.getBody(byte[].class( 方法从exchange对象获取byte[]数组
2. 将byte[]写入文件
3. 由于这是一个zip有效负载，我将文件重命名为.zip文件
4. 然后，我尝试将zip文件的内容读取到String中。

这是代码 -

public String extractMessageFromExchange(Exchange exchange) {
byte[] bytes = exchange.getIn().getBody(byte[].class);
File file = null;
File zipFile = null;
/*
* 1. Dump bytes into a file
* 2. Add ".zip" extension to file
* Now, Unzip the file (It's convoluted, but that's how we receive payload back from downstream)
* 3. Use ZipUtil to get path to the unzipped file
* 4. Use FileUtil to read the contents of the file into a String object
*/
try {
String filePath = zipFileGenPath + zipFileGenSuffix + hyphen + 
incoming;
file = new File(filePath);
FileUtils.writeByteArrayToFile(file, bytes);
zipFile = new File(filePath+zipFileGenExt);
boolean renamed = file.renameTo(zipFile);
log.info("Temp zip file created at - " + zipFile.getPath());
String underlyingXMLFilePath = 
unzipFile(zipFile.getPath(), zipFileGenPath); //gives the path
incomingMessage = FileUtils.readFileToString(new 
File(underlyingXMLFilePath));
return incomingMessage;
} catch (Exception e) {
log.error("Exception occurred while reading byte[] payload into zip 
file : ", e.getMessage());
log.error("Error stacktrace: ", e);
} finally {
deleteFile(zipFile);
}
}

然后是罪魁祸首——

public String unzipFile(final String sourceZipFile, String updateToDir) throws Exception {
ZipFile zipFile = new ZipFile(sourceZipFile);
return unzipFile(zipFile, updateToDir);
}
public String unzipFile(ZipFile zipFile, String updateToDir) throws Exception {
ZipInputStream is = null;
OutputStream os = null;
ZipParameters parameters = new ZipParameters();
parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
parameters.setEncryptFiles(false);
try {
List fileHeaderList = zipFile.getFileHeaders();
for (int i = 0; i < fileHeaderList.size(); i++) {
FileHeader fileHeader = (FileHeader) fileHeaderList.get(i);
if (fileHeader != null) {
String outFilePath = updateToDir + File.separator + fileHeader.getFileName();
File outFile = new File(outFilePath);
is = zipFile.getInputStream(fileHeader);
os = new FileOutputStream(outFile);
int readLen = -1;
byte[] buff = new byte[4096];
while ((readLen = is.read(buff)) != -1) {
os.write(buff, 0, readLen);
}
return outFilePath;
}
}
} finally {
IOUtils.closeQuietly(is);
IOUtils.closeQuietly(os);
}
return null;
}

结果 ->

ZipUtil - Exception occurred while reading byte[] payload into zip file : 
ZipUtil - Error stacktrace: 
net.lingala.zip4j.exception.ZipException: unexpected end of file when reading short buff
at net.lingala.zip4j.core.HeaderReader.readIntoBuff(HeaderReader.java:1094)
at net.lingala.zip4j.core.HeaderReader.readCentralDirectory(HeaderReader.java:221)
at net.lingala.zip4j.core.HeaderReader.readAllHeaders(HeaderReader.java:94)
at net.lingala.zip4j.core.ZipFile.readZipInfo(ZipFile.java:425)
at net.lingala.zip4j.core.ZipFile.getFileHeaders(ZipFile.java:688)
at ZipUtil.unzipFile(ZipUtil.java:230)
at ZipUtil.unzipFile(ZipUtil.java:218)
at ZipUtil.extractMessageFromExchange(ZipUtil.java:96)

知道发生了什么吗？ 附言。我正在Unix盒子中尝试这些。

Answer 1

我设法解决了它。问题不在于压缩逻辑或zip4j，而是在解压缩开始之前的一个顽皮的小"convertBodyToString"方法。这基本上导致了原始压缩消息的损坏，因此解压缩无法成功。

据你所知，文本末尾的一个流浪~字符破坏了它。