在 Swift 3.0 中使用 XMPP 阻止和取消阻止用户

Question

我已经审查了很多博客和网站，用于阻止和取消阻止在 Swift 中使用 XMPP 的用户。但是，这些例子都不适合我。任何有片段代码的人，请与我分享。谢谢。

func blockUser(userJID: String) {
   let privacyList = XMPPPrivacy(dispatchQueue: DispatchQueue.main)
    privacyList?.activate(xmppStream)
    privacyList?.addDelegate(self, delegateQueue: DispatchQueue.main)
     let privacyElement = XMPPPrivacy.privacyItem(withType: "jid", value: userJID, action: "deny", order: 0)
    XMPPPrivacy.blockIQs(privacyElement)
    XMPPPrivacy.blockMessages(privacyElement)
    XMPPPrivacy.blockPresence(in: privacyElement)
}

Answer 1

您需要使用 XEP 0191 来实现阻止功能。

代码（迅捷3.0）：

     //Block / Unblock User
    var xmppBlocking: XMPPBlocking?

添加阻止用户

和取消阻止用户

//Blocking Managment
    self.xmppBlocking = XMPPBlocking()
    self.xmppBlocking!.autoRetrieveBlockingListItems = true
    self.xmppBlocking!.autoClearBlockingListInfo = true;
    self.xmppBlocking!.addDelegate(self, delegateQueue: DispatchQueue.main)
    self.xmppBlocking!.activate(self.xmppStream)
    self.xmppBlocking?.retrieveBlockingListItems()
    xmppBlocking?.blockJID(user.jid) 
    xmppBlocking?.unblockJID(user.jid)

extension BlockListVC : XMPPBlockingDelegate{
        public func xmppBlocking(_ sender: XMPPBlocking!, didBlockJID xmppJID: XMPPJID!){
           //Successfully blocked
        }
        public func xmppBlocking(_ sender: XMPPBlocking!, didNotBlockJID xmppJID: XMPPJID!, error: Any!){
            if(error is NSError){
                //print error message
            }
        }
        public func xmppBlocking(_ sender: XMPPBlocking!, didReceivedBlockingList blockingList: [Any]!) {
            //Received blocked list in this delegate method
        }
   public func xmppBlocking(_ sender: XMPPBlocking!, didUnblockJID xmppJID: XMPPJID!) {
    }
    public func xmppBlocking(_ sender: XMPPBlocking!, didNotUnblockJID xmppJID: XMPPJID!, error: Any!) {
        if(error is NSError){
        }
    }
  }