如何读取JSON_DECODE结果并将其转储

Question

我的JSON响应有一个小问题。

我将其倒在PHP代码中，结果是我在此处附加的

如何转储statusText？

我已经尝试将其解码，并且也尝试过：

dump($myVar['statusText']);

或类似的东西

(要获得我发布的JSON的转储，我刚刚做过 dump($myVar);(

JsonResponse {#325
  #data: "{"code":"OK","status":"ok","data":{"UUID":"f239ae18-98af-4224-8b4f-7713c71a5576","order":{something here },"orderRows":[something else here}}"
  #callback: null
  #encodingOptions: 271
  +headers: ResponseHeaderBag {#326
    #computedCacheControl: array:2 [
      "no-cache" => true
      "private" => true
    ]
    #cookies: []
    #headerNames: array:4 [
      "content-type" => "Content-Type"
      "access-control-allow-origin" => "Access-Control-Allow-Origin"
      "cache-control" => "Cache-Control"
      "date" => "Date"
    ]
    #headers: array:4 [
      "content-type" => array:1 [
        0 => "application/json; charset=utf-8"
      ]
      "access-control-allow-origin" => array:1 [
        0 => "*"
      ]
      "cache-control" => array:1 [
        0 => "no-cache, private"
      ]
      "date" => array:1 [
        0 => "Mon, 06 May 2019 08:15:28 GMT"
      ]
    ]
    #cacheControl: []
  }
  #content: "{"code":"OK","status":"ok","data":{"UUID":"f239ae18-98af-4224-8b4f-7713c71a5576","order":{something},"orderRows":[something else}}"
  #version: "1.0"
  #statusCode: 200
  #statusText: "OK"
  #charset: null
}

只是想看看 "status" => 'ok'，我的生活将是完美的：D

Answer 1

查看此输出，看起来代码也存储在内容中。

"状态"："确定"

因此，按照getData()方法的此文档，您应该能够检索状态：

$data = $myVar->getData();
var_dump($data->status);

预计这会返回一串" OK"。