在Python代码中使用numpy 1.18.1
`def printBoard(self(:current=self.playerother=self-layer%2+1
currBin = '{:049b}'.format(self.current_position)
currRev = currBin[::-1]
cArr = (np.fromstring(currRev,'u1') - ord('0'))*current
other_position = self.current_position^self.mask
othBin = '{:049b}'.format(other_position)
othRev = othBin[::-1]
oArr = (np.fromstring(othRev,'u1') - ord('0'))*other
tArr = oArr+cArr
brd = np.reshape(tArr,(7,7),order = 'F')
for y in range(bitBoard.HEIGHT,-1,-1):
for x in range(bitBoard.WIDTH):
print(brd[y,x],end = ' ')
print()
print()
`
线路:
cArr = (np.fromstring(currRev,'u1') - ord('0'))*current
发出以下警告:
DeprecationWarning: The binary mode of fromstring is deprecated, as it behaves surprisingly on unicode inputs. Use frombuffer instead
cArr = (np.fromstring(currRev,'u1') - ord('0'))*current
将"fromstring"替换为"fromsbuffer"会出现以下错误:
cArr = (np.frombuffer(currRev,'u1') - ord('0'))*current
TypeError: a bytes-like object is required, not 'str'
尽管我在谷歌上搜索了一下,但还是找不到应该用什么。有人能帮忙吗?
谢谢。
Alan
代码的相关部分是生成currRev
的部分。由此,我可以构建这个例子:
In [751]: astr = '{:049b}'.format(123)[::-1]
In [752]: astr
Out[752]: '1101111000000000000000000000000000000000000000000'
您的警告:
In [753]: np.fromstring(astr, 'u1')
/usr/local/bin/ipython3:1: DeprecationWarning: The binary mode of fromstring is deprecated, as it behaves surprisingly on unicode inputs. Use frombuffer instead
#!/usr/bin/python3
Out[753]:
array([49, 49, 48, 49, 49, 49, 49, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48,
48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48,
48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48],
dtype=uint8)
frombuffer
想要一个字节串,所以让我们创建一个:
In [754]: astr.encode()
Out[754]: b'1101111000000000000000000000000000000000000000000'
In [755]: np.frombuffer(astr.encode(),'u1')
Out[755]:
array([49, 49, 48, 49, 49, 49, 49, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48,
48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48,
48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48],
dtype=uint8)
其余部分:
In [756]: _-ord('0')
Out[756]:
array([1, 1, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0], dtype=uint8)
获得相同阵列的另一种方法:
In [758]: np.array(list(astr),'uint8')
Out[758]:
array([1, 1, 0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0], dtype=uint8)