我有下面的服务，我正试图用基类继承我的服务，这样我就可以把所有常量选项数据放在基类中
服务类
import { BaseNotification } from './baseNotification';
declare let toastr: any;
@Injectable({
providedIn: 'root'
})
export class NotificationService extends BaseNotification
{
constructor() {
super();
toastr.options = this.options;
}
success(message: string, title?: string): void {
toastr.success(message, title);
}
BaseNotification类
export class BaseNotification {
options = {};
constructor(){
this.options = {
"closeButton": true,
"positionClass": "toast-top-right",
"preventDuplicates": false,
"showDuration": "300",
"hideDuration": "1000",
"timeOut": "1000",
"extendedTimeOut": "1000",
"showEasing": "swing",
"hideEasing": "linear",
"showMethod": "fadeIn",
"hideMethod": "fadeOut"
}
}
}
但它不识别基类。我不想创建一个单独的子服务。我做错什么了吗？
toast可能会在基类中声明，notificationService实现逻辑。
@Injectable(｛providedIn:'root'｝(导出类NotificationService扩展BaseNotification｛
构造函数(toast：ToastrService({super(烤面包机(
}成功(消息，标题({return super.tother.success(消息、标题(；}
}
我不确定是否在类外声明let语句，但如果你想将超类常量初始化为子类，你可以创建实例变量并初始化为它，如下所示：
@Injectable({
providedIn: 'root'
})
export class NotificationService extends BaseNotification
{
public toastr: any;
constructor() {
super();
toastr = this.options;
}
-----
------
}
以下是堆叠式示例