Opsgenie powershell 警报帖子不起作用

Question

我已经使用 Python 成功发布了一个警报帖子，但无法让我的 powershell 警报创建正常工作。我只是在我的响应中得到一堵 HTML 墙，没有创建警报。消息是唯一的必填字段。 这是我正在使用的，它不起作用

$api = "XXX"
$URI = "https://api.opsgenie.com/v2/alerts"
$head = @{"Authorization" = "GenieKey $api"}
$body = @{
message = "testing";
responders = 
]@{
name = "TEAMNAMEHERE";
type = "team"
}]
} | ConvertTo-Json
$request = Invoke-RestMethod -Uri $URI -Method Post -Headers $head -ContentType "application/json" -Body $body
$request

这是我制作的python代码，它工作得很好。

import requests
import json

def CreateOpsGenieAlert(api_token):
header = {
"Authorization": "GenieKey " + api_token,
"Content-Type": "application/json"
}
body = json.dumps({"message": "testing",
"responders": [
{
"name": "TEAMNAMEHERE",
"type": "team"
}
]
}
)
try:
response = requests.post("https://api.opsgenie.com/v2/alerts",
headers=header,
data=body)
jsontemp = json.loads(response.text)
print(jsontemp)
if response.status_code == 202:
return response
except:
print('error')
print(response)

CreateOpsGenieAlert(api_token="XXX")

编辑：所以我发现它与我的"响应者"部分有关。它与 [ ]...但我一直无法弄清楚到底是什么。如果我删除它们，它将不起作用。如果我把第一个转过来，它就行不通了。我可以成功创建警报，但是不断收到以下错误：

] : The term ']' is not recognized as the name of a cmdlet, function, script file, or operable program. Check the spelling of the name, or if a path was included, verify that the path is correct and try again.
At \fileTechuserpowershell scripts.not workingOpsGenieAlert.ps1:7 char:17
+                 ]@{
+                 ~
+ CategoryInfo          : ObjectNotFound: (]:String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException

Answer 1

您需要将$body转换为JSON

$api = "XXX"
$URI = "https://api.opsgenie.com/v2/alerts"
# Declare an empty array 
$responders = @()
# Add a new item to the array
$responders += @{
name = "TEAMNAMEHERE1"
type = "team1"
}
$responders += @{
name = "TEAMNAMEHERE2"
type = "team2"
}
$body = @{
message    = "testing"
responders = $responders
} | ConvertTo-Json
$invokeRestMethodParams = @{
'Headers'     = @{
"Authorization" = "GenieKey $api"
}
'Uri'         = $URI
'ContentType' = 'application/json'
'Body'        = $body
'Method'      = 'Post'
}
$request = Invoke-RestMethod @invokeRestMethodParams