向上/向下滑动无法正常工作

嗨，我想用表格显示一些搜索结果。在我的代码中，基本详细信息显示在一个表中，如果我们想查看更多详细信息，您必须单击查看更多选项。隐藏的详细信息也显示在单独的表格中。但我的代码有问题。如果我的数据库中有多个搜索结果，则会根据我的意愿显示第一人称的详细信息。这意味着我想看到更多的细节，我想点击查看更多，然后它滑下隐藏表。但搜索结果的其余部分也显示隐藏的表。此外，如果我点击其余部分的查看更多选项，它会再次滑下第一人称表格的隐藏表格。我在这里附上了我的代码。你能帮我解决这个问题吗？

<body>
<div class="container"> <!-- container -->
<div class="row" id="main-content">
<div class="span8">
<div class="well">    <!-- -start of well class -->
<?php
dbConnect();
$district = $_POST['district'];
$category = $_POST['catID'];
$subject  = $_POST['subID'];
//get the category name
$get_cat_name = mysql_query("SELECT catName FROM tutor_category WHERE catID='{$category}' ");
while($row = mysql_fetch_assoc($get_cat_name ))
{
    $cat_name = $row['catName'];
}
//get the subject name
$get_sub_name = mysql_query(" SELECT subName FROM tutor_subjects WHERE catID='{$category}' AND subID='{$subject}'");
while($row = mysql_fetch_assoc($get_sub_name ))
{
    $sub_name = $row['subName'];
}
?>

<!-- ****************** Heading Table *******************-->
<table class="table table-bordered">
            <tr>
                <th> <?php echo $district." District - ". $cat_name ." - ". $sub_name ?> </th>
        </tr>
</table>            
<!-- ****************** end of heading table *******************-->

<?php
//get tutor IDs
$get_tutor_id = mysql_query(" SELECT DISTINCT tutorID FROM tutor_register_subjects WHERE district='{$district}' AND catID='{$category}' AND subID='{$subject}' ");

while($row = mysql_fetch_assoc($get_tutor_id)) // first
{
    $tutor_id = $row['tutorID'];
$query = mysql_query(" SELECT * FROM tutor WHERE tutorID='{$tutor_id}' ");
while($row = mysql_fetch_assoc($query))
{ // second 
    $fname = $row['firstName'];
    $lname = $row['lastName'];
    $nic   = $row['nic'];
  $gender = $row['gender'];
    $education = $row['education'];
    $address = $row['address'];
    $profession= $row['profession'];
    $email = $row['email'];
    $cnum = $row['contactNum'];
  $avatar = $row['avatar'];
} // second
?>
<div class="control-group">
<!-- basic details -->
<table class="table table-bordered">    
  <tr>
    <td width="120" rowspan="4"><?php echo "<img src='uploads/".$avatar."' height='120' width='100'>"?></td>
    <th width="120">Name</th>
    <td><?php echo $fname." ". $lname?></td>
  </tr>
  <tr>
    <th>NIC</th>
    <td><?php echo $nic ?></td>
  </tr>
  <tr>
    <th>Gender</th>
    <td><?php echo $gender ?></td>
  </tr>
  <tr>
    <td colspan="2"><a class="more">View More</a>&nbsp;&nbsp;&nbsp;&nbsp;<a class="less">View Less</a></td>
  </tr>
</table>
</div>
<!-- end of basic details --> 
<!-- more details-->
<div class="control-group" id="more">
<table class="table table-bordered">
 <tr>
    <th>Contact Number</th>
    <td><?php echo $cnum ?></td>
  </tr>
  <tr>
    <th>Email</th>
    <td><?php echo $email ?></td>
  </tr>
  <tr>
    <th>Address</th>
    <td><?php echo $address ?></td>
  </tr>
  <tr>
    <th>Education</th>
    <td><?php echo $education ?></td>
  </tr>
  <tr>
    <th>Work Place</th>
    <td><?php echo $profession ?></td>
  </tr>
</table>
</div>
<!-- end of more details-->    
<legend></legend>
<?php 
} // first
?>
</div> <!-- -start of well class -->    
</div> <!-- end span12 class -->
</div> <!-- end of row class -->
</div> <!-- container -->
<!-- view more script-->
<script src="../js/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("#more").hide();
  $(".less").click(function(){
    $("#more").slideUp(1000);
  });
  $(".more").click(function(){
    $("#more").slideDown(1000);
  });
});
</script>
</body>

发生的事情是$("#more")更多地选择每个ID为的div，并将其更改为

为每个.less和.more提供对当前用户唯一的东西：

<div class="less" data-id="<?php echo $person_id; ?>">Show less</div>
<div class="more" data-id="<?php echo $person_id; ?>">Show more</div>

然后在实际数据所在的#more中，对相同的进行处理

<div id="more-<?php echo $person_id; ?>">More information here</div>

现在在jQuery中，选择正确的id:

$(".less").click(function(){
   $("#more-"+ $(this).attr('data-id')).slideUp(1000);
});
$(".more").click(function(){
    $("#more-"+ $(this).attr('data-id')).slideDown(1000);
});

你现在有效地做的是告诉jQuery选择带有例如id="more-15"的div，以防你点击了属性为data-id="15"的.more，从而选择正确的div：）

注意：您不必使用div就可以做到这一点。这也将解决无效的HTML，因为您有大量具有相同id的的元素

请参阅：http://ejohn.org/blog/html-5-data-attributes/

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