我正在使用PL/SQL过程来插入一个以前生成的表格中的表:
INSERT INTO REI_LABOUR_COST (DEALER_NUMBER, DEALER_STATUS, BILLING_PARTNER, BSI_GW, YEAR, QUANTITY_FRU, LABOUR_EUR, LABOUR_LOCAL, REQUESTED_RATE)
select c001 as DEALER_NUMBER
, c002 as DEALER_STATUS
, c003 as BILLING_PARTNER
, c004 as BSI_GW
, c005 as YEAR
, c006 as QUANTITY_FRU
, c007 as LABOUR_EUR
, c008 as LABOUR_LOCAL
, c009 as REQUESTED_RATE
from apex_collections col
where collection_name = 'COLLECTION' and seq_id != 1
order by seq_id;
但它行不通。没有错误消息或该过程失败的其他迹象,但在最后一个表中没有显示任何结果。
第一个问题,有什么迹象我做错了什么?
第二个问题,如果命令失败,我会在哪里看到错误消息?我可以在某个地方启用它吗?
在将插入插入数据库之前,必须为每个成员属性更新APEX集合。
第一个顶点进程:在提交和计算之前
declare
y pls_integer := 0;
v_msg varchar2(4000);
begin
if not apex_collection.collection_exists(p_collection_name=>'COLLECTION') then
wwv_flow.debug('No Apex collection found!');
else
for x in (select * from apex_collections where collection_name = 'COLLECTION' and seq_id != 1 order by seq_id)
loop
y := y+1;
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>1,p_attr_value=>wwv_flow.g_f01(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>2,p_attr_value=>wwv_flow.g_f02(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>3,p_attr_value=>wwv_flow.g_f03(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>4,p_attr_value=>wwv_flow.g_f04(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>5,p_attr_value=>wwv_flow.g_f05(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>6,p_attr_value=>wwv_flow.g_f06(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>7,p_attr_value=>wwv_flow.g_f07(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>8,p_attr_value=>wwv_flow.g_f08(y));
apex_collection.update_member_attribute (p_collection_name=> 'COLLECTION', p_seq=> x.seq_id,p_attr_number =>9,p_attr_value=>wwv_flow.g_f09(y));
end loop;
end if;
exception when others then
v_msg := ''||sqlerrm;
wwv_flow.debug('ERR: '||v_msg);
end;
第二个顶点进程:提交后
declare
v_msg varchar2(4000);
begin
for x in (select * from apex_collections where collection_name = 'COLLECTION' and seq_id != 1 order by seq_id)
loop
begin
INSERT INTO REI_LABOUR_COST (DEALER_NUMBER, DEALER_STATUS, BILLING_PARTNER, BSI_GW, YEAR, QUANTITY_FRU, LABOUR_EUR, LABOUR_LOCAL, REQUESTED_RATE)
values(x.c001, x.c002, x.c003, x.c004, x.c005, x.c006, x.c007, x.c008, x.c009);
exception when others then
v_msg := ''||sqlerrm;
wwv_flow.debug('ERR_1: '||v_msg);
end;
end loop;
exception when others then
v_msg := ''||sqlerrm;
wwv_flow.debug('ERR_2: '||v_msg);
end;
我认为您不能这样参考SEQ_ID。
使用 APEX_COLLECTION.DELETE_MEMBER
摆脱seq_id 1.
例如。
BEGIN
APEX_COLLECTION.DELETE_MEMBER(
p_collection_name => 'COLLECTION',
p_seq => '1');
END;
然后按正常继续进行。
编辑 - 失败的原因是错误的数据类型错误。如果您检查调试器,则应该可以看到。