构造DeepDiff结果的Python dict



我有一个deepdiff结果,可以通过比较两个JSON文件获得。我必须从deepdiff结果中构造一个python词典。

json1 = {"spark": {"ttl":3, "poll":34}}
json2 = {"spark": {"ttl":3, "poll":34, "toll":23}, "cion": 34}
deepdiffresult = {'dictionary_item_added': {"root['spark']['toll']", "root['cion']"}}
expecteddict = {"spark" : {"toll":23}, "cion":34}

如何实现?

可能有一种更好的方法可以做到这一点。但是您可以将返回的字符串和链条解析为一个新词典,并带有您想要的结果。

json1 = {"spark": {"ttl":3, "poll":34}}
json2 = {"spark": {"ttl":3, "poll":34, "toll":23}, "cion": 34}
deepdiffresult = {'dictionary_item_added': {"root['spark']['toll']", "root['cion']"}}
added = deepdiffresult['dictionary_item_added']
def convert(s, j):
    s = s.replace('root','')
    s = s.replace('[','')
    s = s.replace("'",'')
    keys = s.split(']')[:-1]
    d = {}
    for k in reversed(keys):
        if not d:
            d[k] = None
        else:
            d = {k: d}
    v = None
    v_ref = d
    for i, k in enumerate(keys, 1):
        if not v:
            v = j.get(k)
        else:
            v = v.get(k)
        if i<len(keys):
            v_ref = v_ref.get(k)
    v_ref[k] = v
    return d
added_dict = {}
for added_str in added:
    added_dict.update(convert(added_str, json2))
added_dict
#returns:
{'cion': 34, 'spark': {'toll': 23}}

简单答案,在Python中,具有一个称为DICEDDIFFER函数的内构建。你能尝试一下吗?

$ pip install dictdiffer

示例:

from dictdiffer import diff
result = diff(json1, json2)
print result == {"spark" : {"toll":23}, "cion":34}

参考:dictdiffer

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