为什么dict设置相同的atfer循环

Question

我是Python的初学者。

我正在检索数据并将其保存到dict。当第二次循环时，它会替换我的第一个键值。

您可以找到第二个Atfer match_chlDict的输出，键"1"的值被键"2"替换。

我自己没有办法解决，请帮忙。非常感谢。

这是match_details中的原始

[{'LINENUM': '1', 'LINESTATUS': '0', 'LINEORDER': '1', 'LINE': '9.5', 'H': '100@1.75', 'L': '100@1.95'}, {'LINENUM': '2', 'LINESTATUS': '1', 'LINEORDER': '2', 'LINE': '10.5', 'H': '100@2.20', 'L': '100@1.59'}]

代码

match_chl={}
match_chlDict={}
for chl in match_details['chl']:          
print("Current match_chlDict") 
print(match_chlDict)
match_chl['chlLINE']=chl['LINE']
match_chl['chlH']=replace100(chl['H'])
match_chl['chlL']=replace100(chl['L']) 
#Write match_chl to dict by "LINENUM" as key                   
match_chlDict[chl['LINENUM']]=match_chl    
print("Atfer match_chlDict") 
print(chl['LINENUM'])
print(match_chlDict)

输出

Curr match_chlDict
{}

Atfer match_chlDict

1
{'1': {'chlLINE': '9.5', 'chlH': '1.75', 'chlL': '1.95'}}

当前匹配_ hlDict

{'1': {'chlLINE': '9.5', 'chlH': '1.75', 'chlL': '1.95'}}

Atfer match_chlDict

2
{'1': {'chlLINE': '10.5', 'chlH': '2.20', 'chlL': '1.59'}, '2': {'chlLINE': '10.5', 'chlH': '2.20', 'chlL': '1.59'}}

Answer 1

每次在循环中重新初始化match_chl={}，否则它将替换字典中的引用。

match_chl = {}
match_chlDict = {}
for chl in m:
print("Current match_chlDict")
print(match_chlDict)
match_chl['chlLINE'] = chl['LINE']
match_chl['chlH'] = 'a'
match_chl['chlL'] = 'b'
match_chlDict[chl['LINENUM']] = match_chl
print("Atfer match_chlDict")
print(chl['LINENUM'])
print(match_chlDict)
match_chl = {}

希望这能有所帮助！！

Answer 2

def replace100(str):
return(str.replace("100@",""))
for chl in data:
match_chl = {}
match_chl['chlLINE'] = chl['LINE']
match_chl['chlH'] = replace100(chl['H'])
match_chl['chlL'] = replace100(chl['L'])
match_chlDict[chl['LINENUM']] = match_chl
match_chlDict

我不确定你在寻找什么，但如果你想把第一个元素作为关键字，我想上面的代码是有效的。我想你的错误可能是把值存储在同一个match_chl中。每次循环开始时都应该重置其值。