使用二维数组连接 4

Question

如果一行中有 4 个具有相同的值，我想检查大小为 8x8 的多维数组，然后调用另一个方法。IF as a example the positions 0/0, 0/1, 0/2, 0/3 have the value 1然后调用方法finish(1)。"但这应该也适用于对角线，比如

Answer 1

您可以创建一个函数并为数组的每个元素调用它。成功后，它将返回值，调用 finish 函数并结束循环。像这样：

int Check(int[,] a,int x, int y)
{   
  for(int n =-1;n<2;n++)
  {
    for(int m =-1;m<2;m++)
    {
        if(n!= 0 || m!= 0)
        {
            int previousX = x;
            int previousY = y;
            int nextX = previousX+n;
            int nextY = previousY+m;
            int counter = 0;                
            while((nextX >= 0 && nextX < 8 && nextY >= 0 && nextY < 8) 
                && (a[previousX,previousY] ==a[nextX,nextY]))
            {
                counter++;  
                previousX += n;
                previousY += m;
                nextX += n;
                nextY += m;                       
                if(counter >= 3)
                    return a[x,y];            
            }
        }
     }
  }
  return -1; //That means nothing was found
}