我面临这个问题2天,但无法解决这个问题。我正在尝试使用JAX-WS调用web服务。服务调用,但其中的对象未被解析。
JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean();
factory.setServiceClass(ICustomer.class);
factory.setAddress("http://localhost:8080/backend/services/CustomerInfo");
ICustomer client = (ICustomer) factory.create();
// Below is the service call. where 'object' is my CustomerInfo object/data
client.saveCustomer(object);
服务实现类:
@WebService(endpointInterface = "com.dev.backend.services.interfaces.ICustomer", serviceName="CustomerInfo")
public class ICustomerImpl implements ICustomer {
public boolean saveCustomer(Object object) {
JAXBContext payloadContext;
try {
payloadContext = JAXBContext.newInstance(CustomerInfo.class);
CustomerInfo o = (CustomerInfo)payloadContext.createUnmarshaller().unmarshal((Node)object); // Line 'error'
} catch (JAXBException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
(CustomerInfo)payloadContext.createUnmarshaller(). unmarshaller ((Node)object)是异常抛出"javax.xml.bind. xml"的行。UnmarshalException:意外元素(uri:", local:"arg0")。期望的元素是<{}customerInfo>"
有谁能帮帮我吗?我正在寻找解决方案2天。谢谢
您有这样的XML节点吗?
<ws:customerInfo> ... </ws:customerInfo>
如果有,请尝试删除"ws"
更新:如果你有一个类似这样的方法:
public ReturnType Method1(
@WebParam(name="RequestType1") RequestType1 request)
尝试将其更改为:
public ReturnType Method1(
@WebParam(name="requestType1") RequestType1 request)
注意,两种情况下的webParam名称是不同的。RequestType1是一个类,webParam的名称也相同。name参数类似于实例名,如果与类名相同,则会被误解。