比较字符串中的单词

Question

我正在尝试比较字符串中的单词。这就是我想做的：

var string1 = "Action, Adventure, Comedy";
var string2 = "Action Horror";
if (string1 have a word from string 2 == true)
{
    alert("found!");
}

我尝试过match（），但在我的情况下，它试图找到"动作恐怖"而不是"动作"和"恐怖"词。

Answer 1

您可以使用

match()和reduce()

var string1 = "Action, Adventure, Comedy";
var string2 = "action Horror";
var strArr = string1.match(/bw+?b/g)
  //getting all words from string one
  .map(function(v) {
    return v.toLowerCase();
  });
//converting strings to lower case for ignoring case
var res = string2.match(/bw+?b/g)
  // getting words from second string
  .reduce(function(a, b) {
    return a || strArr.indexOf(b.toLowerCase()) != -1;
    //checking string in first word  array
  }, false);
  // also set initial value as false since no strings are matched now
console.log(res);

或

var string1 = "Action, Adventure, Comedy";
var string2 = "action Horror";
var res = string2.match(/bw+?b/g)
  // getting words from second string
  .reduce(function(a, b) {
    return a || new RegExp('\b' + b + '\b', 'i').test(string1);
    //checking string in first string
  }, false);
  // also set initial value as false since no strings are matched now
console.log(res);

参考 ： JavaScript/jQuery - 如何检查字符串是否包含特定单词

Answer 2

具有 String.split、String.indexOf 和 Array.foreach 函数的解决方案：

var string1 = "Action, Adventure, Comedy, Horror";
    var string2 = "Action Horror";
    var str1_arr = string1.split(', ');
    str1_arr.forEach(function (v) {
        if (string2.indexOf(v) !== -1) {
            console.log("string '"+ v +"'(from string1) was found in string2 in position " + string2.indexOf(v));
        }
    });
// the output:
string 'Action'(from string1) was found in string2 in position 0
string 'Horror'(from string1) was found in string2 in position 7

https://developer.mozilla.org/ru/docs/Web/JavaScript/Reference/Global_Objects/String/splithttps://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/indexOf

Answer 3

声明两个集合：

    var Set set1,ser2;

将字符串

1 复制到集合 1 中，将字符串 2 复制到集合 2

中

（不知道该怎么做）。 然后有：

var 交集 = new Set（[x for （x of set1） if （set2.has（x））]）;

    if intersection.prototype.size>0

字符串（和集合）都有共同的单词。