问题
我有以下对象图:
AppBundleControllerPerson Object
(
[name:AppBundleControllerPerson:private] => Person Name
[age:AppBundleControllerPerson:private] => 10
[phones:AppBundleControllerPerson:private] => Array
(
[0] => AppBundleControllerTelephone Object
(
[phone:AppBundleControllerTelephone:private] => 221-16-78
)
[1] => AppBundleControllerTelephone Object
(
[phone:AppBundleControllerTelephone:private] => 221-16-78
)
)
)
以及使用来自我的控制器的以下代码进行序列化:
$s = $this->get("serializer")->serialize($person, 'xml');
这给了我以下结果:
<response>
<name>Person Name</name>
<age>10</age>
<phones>
<phone>221-16-78</phone>
</phones>
<phones>
<phone>221-16-78</phone>
</phones>
</response>
使用以下代码的反序列化:
$this->get("serializer")->deserialize($s, 'AppBundleControllerPerson', 'xml');
正在返回以下内容:
AppBundleControllerPerson Object
(
[name:AppBundleControllerPerson:private] => Person Name
[age:AppBundleControllerPerson:private] => 10
[phones:AppBundleControllerPerson:private] => Array
(
[0] => Array
(
[phone] => 221-16-78
)
[1] => Array
(
[phone] => 221-16-78
)
)
)
问题
首先,是否有如下接收xml的方法:
<response>
<name>Person Name</name>
<age>10</age>
<phones>
<telephone>
<phone>221-16-78</phone>
</telephone>
<telephone>
<phone>221-16-78</phone>
</telephone>
</phones>
</response>
第二,我如何将它反序列化回对象图(Person和Telephone),一旦使用简单的反序列化,它将返回一个对象Person和一个电话数组,该数组包含一个关联数组,而不是Telephone
对象。
型号/控制器
这里是我的型号/控制器类:
<?php
namespace AppBundleController;
class Person {
private $name;
private $age;
private $phones;
public function getName() {
return $this->name;
}
public function getAge() {
return $this->age;
}
public function getPhones() {
return $this->phones;
}
public function setName($name) {
$this->name = $name;
}
public function setAge($age) {
$this->age = $age;
}
public function setPhones($phones) {
$this->phones = $phones;
}
}
<?php
namespace AppBundleController;
class Telephone {
private $phone;
public function getPhone() {
return $this->phone;
}
public function setPhone($phone) {
$this->phone = $phone;
}
}
我的控制器方法:
/**
* @Route("/", name="homepage")
*/
public function indexAction(Request $request)
{
$phone1 = new Telephone();
$phone1->setPhone("221-16-78");
$phone2 = new Telephone();
$phone2->setPhone("221-16-78");
$person = new Person();
$person->setName("Person Name");
$person->setAge(10);
$person->setPhones(array($phone1, $phone2));
print_r($person);
$s = $this->get("serializer")->serialize($person, 'xml');
$p = $this->get("serializer")->deserialize($s, 'AppBundleControllerPerson', 'xml');
print_r($p);
}
使用JMS序列化程序的解决方案
通过使用注释(基本上是类型和列表详细信息)向序列化程序提供一些提示,我能够使用JMS序列化程序解决这个问题,如下所示:
<?php
namespace AppBundleController;
use JMSSerializerAnnotationType;
use JMSSerializerAnnotationXmlList;
class Person {
/**
* @Type("string")
*/
private $name;
/**
* @Type("integer")
*/
private $age;
/**
* @Type("array<AppBundleControllerTelephone>")
* @XmlList(entry = "telephone")
*/
private $phones;
public function getName() {
return $this->name;
}
public function getAge() {
return $this->age;
}
public function getPhones() {
return $this->phones;
}
public function setName($name) {
$this->name = $name;
}
public function setAge($age) {
$this->age = $age;
}
public function setPhones($phones) {
$this->phones = $phones;
}
}
<?php
namespace AppBundleController;
use JMSSerializerAnnotationType;
class Telephone {
/**
* @Type("string")
*/
private $phone;
public function getPhone() {
return $this->phone;
}
public function setPhone($phone) {
$this->phone = $phone;
}
}
据我所知,当您执行$this->get('serializer')
时,您得到的是Symfony Serialization组件。我并不完全熟悉它(你会在勾选中看到原因),但他们的文档确实强调了如何处理对象属性,尽管只是为了序列化。
对于您似乎正在寻找的对序列化视图的控制类型,我强烈建议使用JMS序列化程序(和相关的捆绑包),它可以通过注释或外部配置对输出进行更细粒度的控制。在你的情况下,做:
use JMSSerializerAnnotation as Serializer;
class Person
{
/**
* @SerializerType("array<Telephone>")
*/
private $phones;
可能足以获得您正在寻找的双向序列化。