BASH:模式匹配不起作用

Question

我使用的是BASH 3.2。我可以从命令行执行以下操作：

$ build_number=23332
$ if [[ $build_number != +([0-9]) ]]
> then
> echo "Bad Build Number ($build_number). No CPU time for you!"
> else
> echo "Build Number ($build_number) is numeric"
> fi
Build Number (2332) is numeric"

如果我更改build_number to 23332a`，则返回：

Bad Build Number (23332a). No CPU time for you!

现在，我将尝试将其放入我的shell脚本中：

#! /bin/bash
...
#
# Set options
#
while getopts :hu:j:b:p: option
do
    case $option in
        p)  promotion_name="$OPTARG";;
        u)  jenkins_url="$OPTARG";;
        j)  job_name="$OPTARG";;
        b)  build_number="$OPTARG"
            if [[ $build_number != +([0-9]) ]]
            then
                error "Build Number must be numeric"
            fi
        ;;
        h)  printf "n$USAGEn"
            exit 0;;
        *)  error "Invalid Argument";;
    esac
done
shift $(( $OPTIND - 1 ))

当我尝试执行我的程序时，我会得到以下错误：

$ ./promotion.sh -b 238d -jasdad
./promotion.sh: line 55: syntax error in conditional expression: unexpected token `('
./promotion.sh: line 55: syntax error near `+(['
./promotion.sh: line 55: `      if [[ $build_number != +([0-9]) ]]'

那么，我做错了什么？

Answer 1

您需要启用扩展的globbing:

shopt -s extglob

Answer 2

最明显的是加号检查前置字符是否与模式匹配，这里没有前置字符将加号放在