如何从设备获取单独的联系人姓名数组列表和联系人号码数组列表

Question

   ArrayList<String> contacts_list = new ArrayList<String>();
        Cursor c = getContentResolver().query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                null, null, null);
        while (c.moveToNext()) {
            contactName = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
            PhoneNumber = c
                    .getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            contacts_list.add("ContactName:"+contactName + "n" +"ContactNumber:"+PhoneNumber );
        }
        c.close();

在上面的代码中，获取姓名和电话号码，但不分隔联系号码和姓名的数组列表

Answer 1

创建两个列表

 ArrayList<String> contacts_name = new ArrayList<String>();
 ArrayList<String> contacts_number = new ArrayList<String>();
        Cursor c = getContentResolver().query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                null, null, null);
        while (c.moveToNext()) {
            contactName = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
            PhoneNumber = c
                    .getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            contacts_name.add("ContactName:"+contactName);
            contacts_number.add("ContactNumber:"+PhoneNumber );
        }
        c.close();

Answer 2

创建一个这样的类

public class NameContact {
private String name;
private String contact;
public NameContact(String name, String contact) {
    this.name = name;
    this.contact = contact;
}
public String getName() {
    return name;
}
public String getContact() {
    return contact;
}
}

然后制作一个数组列表并在其中添加项目。

ArrayList<NameContact> abc = new ArrayList<NameContact>();
abc.add(new NameContact("your_name","your_contact"));

然后之后放入请求参数使用这个

RequestParams params = new RequestParams();
JSONArray arrayName = new JSONArray();
JSONArray arrayContact = new JSONArray();
for(i = 0;i < contacts.size();i++ ) {
    arrayName.put(contacts.get(i).getName());
    arrayContact.put(contacts.get(i).getContact());    
}
params.put("ContactNameArray",arrayName);
params.put("ContactNumberArray",arrayContact);

Answer 3

你应该使用 pojo 类，或者目前你可以使用它：

Arraylist<HashMap<String,String>> arr_list=new Arraylist<HashMap<String,String>>();
  arr_list.clear();
        Cursor c=getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,null, null, null);

而 (c.moveToNext((( {

        contactName = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
        PhoneNumber = c
                .getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
       HashMap<String,String> map=new HashMap<String,String>();
   map.put("name",""+contactName);
   map.put("number",""+PhoneNumber);    
   arr_list.add(map);   
    }
    c.close();

Log.d("array"，"arr="+arr_list(;

您将有两个键和值，其位置为数组，您可以获得单独的值。