总和每个(数组哈希)perl中的所有值

Question

我有一个名为％hash

的数组哈希

$VAR1 = {
          'reboot' => [
                        4442,
                        3483,
                        541
                      ],
          'prod-dev' => [
                          0,
                          485,
                          3421,
                          242,
                          425,
                          425,
                          484,
                          1,
                          244
                        ]
        };

如何在每个键中添加所有值并像这样一次打印所有值

reboot   : sum
prod-dev : sum

谢谢欢呼

#!/usr/binkj/perl -w
use strict;
use warnings;
use List::Util qw( sum );
use Data::Dumper;
my ($substr, $new_line);
my @fields;
my %hash =();
open(my kj$logs, ">STDOUT") or die $!;
my ($total_sum, $total_t, $tsum);
my (@array, $key, $val);
while (<STDIN>) {
        my @matches;
        chomp;
        next if $_ =~ m/still logged in/;
        next if $_ =~ m/wtmp/;
        next if $_ =~ m/(-d.+?)/;
        next if $_ =~ m/^$/g;
        $_ =~ /(^.*?)s.*?((.*?))/g;
       ($key, $val) = ($1,$2);
        $val =~ s/((|))//g;
        if($val =~ m/d+.*/){
                $val =~ s/+/:/;
                #$val =~ m/(^d.)(:d.:)(:d.s)/g; 
                my ($days, $hrs, $mins) = $val =~ /^(d+):(d+):(d+).$/g;
                $days = $days * 24 * 60;
                $hrs = $hrs * 60;
                $total_t = $days + $hrs + $mins;
                #print $days . ":" . $hrs . ":" . $mins. "n";
                print "$total_t n";
        }else {
                my ($hrs, $mins) = $val =~ /^(d+):(d+).$/g;
                $hrs = $hrs * 60;
                $total_t = $hrs + $mins;
                print "$total_t n";
        }
        push (@{$hash{$key}}, $total_t);
        for my $k (keys(%hash)) {
                printf("%-8s : %dn", $k,sum( @{ $hash->{$k} } ),);
        }
print Dumper (%hash);
close $logs;

这是整个Perl程序

我真的很难解决这个问题，希望你们能帮助我

Answer 1

use List::Util qw( sum );
for my $k (keys(%$VAR1)) {
   printf("%-8s : %dn",
      $k,
      sum( @{ $VAR1->{$k} } ),
   );
}

Answer 2

次要但与上述答案相关的重要区别，并且没有任何外部模块。

foreach $val (keys(%$VAR1)){
        $s=0;
        foreach ( @{$VAR1->{$val}}){
                $s = $_+$s;
        }
        print "$val :- $s ";
}

Answer 3

我设法回答了它，非常感谢您！

foreach my $key ( keys %hash ) {
my $total_sum = 0;              
foreach ( @{$hash{$key}} )  {                   
$total_sum += $_;               
}
print $key . "" . $total_sum . "n";
}

Answer 4

List::Util的函数sum可用于总和：

#!/usr/bin/env perl
use strict;
use warnings;
my %hash = (
    'reboot'   => [ 4442, 3483, 541 ],
    'prod-dev' => [ 0,    485,  3421, 242, 425, 425, 484, 1, 244 ],
);
use List::Util qw( sum );
my @sums;
for my $key ( keys %hash ) {
    my $sum = sum @{ $hash{$key} };
    push @sums, "$key: $sumn";
}
print @sums;