我刚刚看到这在技术上是可行的,我唯一无法解决的错误是每次测试时打印的最后一个 ASCII 字符,我也在不使用 name 变量的情况下对此进行了测试,我的意思是只需在 ASCII 中的任何小写字母上减去 32 应该给我他们的大写字母,它确实如此, 但我很好奇为什么我会得到一个额外的字符,从我在屏幕上看到的显然是 Û。
#include <stdio.h>
main()
{
char name[22];
int i;
fputs("Type your name ",stdout);
fgets(name,22,stdin);
for (i = 0; name[i] != ' '; i = i + 1)
printf("%c",(name[i])-32); /*This will convert lower case to upper */
/* using as reference the ASCII table*/
fflush(stdin);
getchar();
}
也许字符串末尾有一个换行符。
您可以检查字符代码,以便仅转换实际为小写字母的字符:
for (i = 0; name[i] != ' '; i = i + 1) {
char c = name[i];
if (c => 97 && c <= 122) {
c -= 32;
}
printf("%c", c);
}
void read_chararray(char in_array[], int* Length)
{
int Indx = 0, Indx2 = 0, Indx3 = 0; // int declarations for indexs of some loops
char cinput = { 0 }, word[255] = { 0 }, word2[255] = { 0 }; // declaration of cinput and first char array before punctiation removed
for (Indx = 0; (cinput = getchar()) != 'n'; Indx++) { // Loop for getting characters from user stop at <enter>
word[Indx] = cinput; // Placing char into array while changing to lowercase
}
Indx2 = Indx; // Set Indx2 to Indx for loop operation
for (Indx = 0; Indx < Indx2; Indx++) { // Loop to check and replace upper characters with lower
cinput = word[Indx];
if (cinput >= 65 && cinput <= 90) { // If cinput is within the ASCII range 65 and 90, this indicates upper characters
cinput += 32; // Add 32 to cinput to shift to the lower character range within the ASCII table
in_array[Indx] = cinput; // Input new value into array pointer
}
else if (cinput >= 97 && cinput <= 122) // scans if character are lower ASCII, places them in array irraticating punctuation and whitespce
in_array[Indx] = cinput; // Input remaining lower case into array pointer
}
*Length = Indx; // final size of array set to Length variable for future use
}
#include<stdio.h>
void upper(char);
void main()
{
char ch;
printf("nEnter the character in lower case");
scanf("%c", &ch);
upper(ch);
}
void upper( char c)
{
printf("nUpper Case: %c", c-32);
}