Slack API:从Slack通道检索所有成员电子邮件

Question

给定一个空闲通道的名称，是否有方法检索该通道中所有成员的电子邮件列表？我试着查看slack api文档，但找不到实现这一点所需的方法(https://api.slack.com/methods)。

Answer 1

如果你有必要的作用域，你可以检索以频道名称开头的频道所有成员的电子邮件，如下所示：

1. 调用channels.list获取所有频道的列表并将频道名称转换为其ID
2. 使用频道ID调用所需频道的channels.info以获取其成员列表
3. 致电users.list检索所有Slack用户的列表，包括他们的个人资料信息和电子邮件
4. 通过用户ID将渠道成员列表与用户列表进行匹配，以获得正确的用户和电子邮件

请注意，这也适用于使用groups.list和groups.info的专用通道，但前提是与访问令牌相关的用户或机器人程序是该专用通道的成员。

更新2019

强烈建议使用较新的对话.*方法，而不是频道.*和组.*，因为它们更灵活，而且在某些情况下，旧方法不起作用(例如转换的频道)。

Answer 2

这里有一个使用最新API与Python 2或3一起工作的版本。

import os
import requests
SLACK_API_TOKEN='xoxb-TOKENID' # Your token here
CHANNEL_NAME='general' # Your channel here
channel_list = requests.get('https://slack.com/api/conversations.list?token=%s&types=%s' % (SLACK_API_TOKEN, 'public_channel,private_channel,im,mpim')).json()['channels']
for c in channel_list:
if 'name' in c and c['name'] == CHANNEL_NAME:
channel = c
members = requests.get('https://slack.com/api/conversations.members?token=%s&channel=%s' % (SLACK_API_TOKEN, channel['id'])).json()['members']
users_list = requests.get('https://slack.com/api/users.list?token=%s' % SLACK_API_TOKEN).json()['members']
for user in users_list:
if "email" in user['profile'] and user['id'] in members:
print(user['profile']['email'])

请注意，您需要创建一个带有OAuth API令牌的Slack应用程序，并授权以下范围用于所有不同类型的对话：

channels:read
groups:read
im:read
mpim:read
users:read
users:read.email

此外，要从私人频道或聊天中阅读，您需要将您的应用程序添加到工作区，并为您感兴趣的每个频道添加"/init-appname"。

Answer 3

注意：不推荐使用channels.list、channels.info和users.list(于2020年11月25日退役并停止运行)。

替换为conversations.list、conversations.members、users.info

您可以通过以下方式获取电子邮件：

conversations.list-获取Channel Id(公共或私有)的列表

conversations.members-通过Channel Id获取Member Id的列表

users.info-通过Member Id获取Email

Answer 4

以下是python代码：

import requests
SLACK_API_TOKEN = "" # get one from https://api.slack.com/docs/oauth-test-tokens
CHANNEL_NAME = ""
# channel_list = requests.get('https://slack.com/api/channels.list?token=%s' % SLACK_API_TOKEN).json()['channels']
# channel = filter(lambda c: c['name'] == CHANNEL_NAME, channel_list)[0]
# channel_info = requests.get('https://slack.com/api/channels.info?token=%s&channel=%s' % (SLACK_API_TOKEN, channel['id'])).json()['channel']
# members = channel_info['members']
channel_list = requests.get('https://slack.com/api/groups.list?token=%s' % SLACK_API_TOKEN).json()['groups']
channel = filter(lambda c: c['name'] == CHANNEL_NAME, channel_list)[0]
channel_info = requests.get('https://slack.com/api/groups.info?token=%s&channel=%s' % (SLACK_API_TOKEN, channel['id'])).json()['group']
print channel_info
members = channel_info['members']
users_list = requests.get('https://slack.com/api/users.list?token=%s' % SLACK_API_TOKEN).json()['members']
users = filter(lambda u: u['id'] in members, users_list)
for user in users:
first_name, last_name = '', ''
if user['real_name']:
first_name = user['real_name']
if ' ' in user['real_name']:
first_name, last_name = user['real_name'].split()
# print "%s,%s,%s" % (first_name, last_name, user['profile']['email'])
print "%s" % (user['profile']['email'])

Answer 5

我刚刚制作了一个小Ruby脚本，它从一个松弛通道中检索所有成员，并以CSV格式返回。

脚本：https://github.com/olivernadj/toolbox/tree/master/slack-members

示例：

$ ./membersof.rb -t xoxp-123456789A-BCDEF01234-56789ABCDE-F012345678 -g QWERTYUIO
first_name,last_name,email
John,Doe,[e-mail]
Jane,Doe,[e-mail]

Answer 6

根据@Lam的回答，我将其修改为使用python3。

import requests
SLACK_API_TOKEN = "" # get one from https://api.slack.com/docs/oauth-test-tokens
CHANNEL_NAME = ""
# channel_list = requests.get('https://slack.com/api/channels.list?token=%s' % SLACK_API_TOKEN).json()['channels']
# channel = filter(lambda c: c['name'] == CHANNEL_NAME, channel_list)[0]
# channel_info = requests.get('https://slack.com/api/channels.info?token=%s&channel=%s' % (SLACK_API_TOKEN, channel['id'])).json()['channel']
# members = channel_info['members']
channel_list = requests.get('https://slack.com/api/groups.list?token=%s' % SLACK_API_TOKEN).json()['groups']
for c in channel_list:
if c['name'] == CHANNEL_NAME:
channel = c
channel_info = requests.get('https://slack.com/api/groups.info?token=%s&channel=%s' % (SLACK_API_TOKEN, channel['id'])).json()['group']
print(channel_info)
members = channel_info['members']
users_list = requests.get('https://slack.com/api/users.list?token=%s' % SLACK_API_TOKEN).json()['members']
for user in users_list:
if "email" in user['profile']:
print(user['profile']['email'])

Answer 7

使用slack Ruby客户端的Ruby解决方案：

范围：

• channels:read
• users.profile:read
• users:read.email
• users:read

require 'slack-ruby-client'
Slack.configure do |config|
config.token = ENV['SLACK_TOKEN_IN_BASH_PROFILE']
end
client = Slack::Web::Client.new
CH = '#channel-name'
client.conversations_members(channel: CH).members.each do |user|
puts client.users_profile_get(user: user).profile.email
end

Answer 8

我不确定这些是否都过时了，但我无法让其中任何一个工作。我发现最好的方法是使用client.conversations_members方法查找所有用户ID，然后获取这些用户的电子邮件。

import slack
def get_channel_emails(channel_id:str)-> list:
client = slack.WebClient(token=os.getenv("SLACK_TOKEN"))
result = client.conversations_members(channel= channel_id)
emails = []
for user in result['members']:
info = client.users_info(user = user).data
if 'email' in info['user']['profile'].keys():
emails.append(info['user']['profile']['email'])
return emails

一些值得注意的障碍是：

1. slack包实际上是slackclient，因此使用pip install slackclient而不是

2. channel_id不是通道名称，而是给通道的代码松弛。它可以在web浏览器版本路径中找到，格式为CXXXXXXXXXX。

Answer 9

如果没有编码，您需要从Slack频道获取所有用户的电子邮件：

转到频道设置；复制成员电子邮件地址"；。

使用Slack API：

对话列表-获取通道Id(公共或私人)列表

对话。成员-通过通道Id 获取成员Id列表

users.info-按会员Id 获取电子邮件

Answer 10

使用python3和包"slackclient"这里

pip3安装slackclient

def get_channel_emails(channel_id: str):
slack_api_bot_token = 'YOUR_BOT_TOKEN'

## Require BOT permission ##

# channels:read
# groups:read
# im:read
# mpim:read
# users:read
client = slack.WebClient(token=slack_api_bot_token)
result = client.conversations_members(channel=channel_id)
i = 0
for user in result['members']:
#print(user)
info = client.users_info(user=user).data
i = i + 1
#print(info)
member_id = info['user']['id']
team_id = info['user']['team_id']
display_name = info['user']['name']
real_name = info['user']['real_name']
phone = info['user']['profile']['phone']
email = info['user']['profile']['email']
if not member_id:
member_id = 'null'
elif not team_id:
team_id = 'null'
elif not display_name:
display_name = 'null'
elif not real_name:
real_name = 'null'
elif not phone:
phone = 'null'
elif not email:
email = 'null'
print(f'{i},{real_name},{display_name},{team_id},{member_id},{email},{phone}')

def main():
#channel id: https://app.slack.com/huddle/TB37ZG064/CB3CF4A7B
#if end of URL string starts with "C", it means CHANNEL
get_channel_emails('CB3CF4A7B')