404 Page NoT Found甚至Tomcat也没有显示任何错误

我试图在eclipse上运行这个简单的例子。当我运行服务器时，它没有显示任何错误。但在浏览器中，它显示404错误页面未找到。我不明白错误是什么。我也使用了我的WEB-INF/Lib文件夹中的所有jar文件。

代码片段如下:

类HELLOWORLDACTION

     package com.action;
        import javax.servlet.http.HttpServletRequest;
        import javax.servlet.http.HttpServletResponse;
        import org.apache.struts.action.Action;
        import org.apache.struts.action.ActionForm;
        import org.apache.struts.action.ActionForward;
        import org.apache.struts.action.ActionMapping;
        import com.form.HelloWorldForm;
        public class HelloWorldAction extends Action{
            public ActionForward execute(ActionMapping mapping,ActionForm form,
                    HttpServletRequest request,HttpServletResponse response) throws Exception {
                HelloWorldForm helloWorldForm = (HelloWorldForm) form;
                helloWorldForm.setMessage("Hello World! Struts");
                return mapping.findForward("success");}
        }

类HelloWorldForm

package com.form;
     import org.apache.struts.action.ActionForm;
     public class HelloWorldForm extends ActionForm{
     String message;
   public String getMessage() {
   return message;
  }
     public void setMessage(String message) {
   this.message = message;
  }
 }

struts - config . xml

    <?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE struts-config PUBLIC 
    "-//Apache Software Foundation//DTD Struts Configuration 1.3//EN" 
    "http://jakarta.apache.org/struts/dtds/struts-config_1_3.dtd">
    <struts-config>
        <form-beans>
            <form-bean name="helloWorldForm" 
                type="com.form.HelloWorldForm"/>
        </form-beans>
        <action-mappings>
            <action path="/helloWorld"
                type="com.action.HelloWorldAction"
                name="helloWorldForm">
                <forward name="success" path="/HelloWorld.jsp"/>
                </action>
        </action-mappings>
    </struts-config>

web . xml

 <?xml version="1.0" encoding="UTF-8"?>
 <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
            <display-name>Maven Struts Examples</display-name> 
          <servlet>
            <servlet-name>action</servlet-name>
            <servlet-class>
                org.apache.struts.action.ActionServlet
            </servlet-class>
            <init-param>
                <param-name>config</param-name>
                <param-value>
                 /WEB-INF/struts-config.xml
                </param-value>
            </init-param>
            <load-on-startup>1</load-on-startup>
          </servlet>
          <servlet-mapping>
               <servlet-name>action</servlet-name>
               <url-pattern>*.do</url-pattern>
          </servlet-mapping>
        </web-app>

HelloWorld.jsp

    <%@ page language="java" contentType="text/html; charset=ISO-8859-1"
        pageEncoding="ISO-8859-1"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <%@taglib uri="http://struts.apache.org/tags-bean" prefix="bean"%>
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Insert title here</title>
    </head>
    <body>
    <h1><bean:write name="helloWorldForm" property="message" />
    </h1>
    </body>
    </html>

听起来您使用了错误的url。Tomcat通常有一个名为webapps的文件夹，用于部署在该服务器上的应用程序。要找出配置，在Eclipse中，打开Server选项卡，找到Tomcat服务器并双击它。

应该会出现一个属性面板，底部有两个选项卡:Overview和Modules。点击Modules，你应该会看到你的应用程序的路径。对我来说，它的形式是:/webapps/<project name>

您的完整url将是localhost:8080/webapps/<project name>/anystringhere.do，因为您将应用程序(localhost:8080/webapps/<project name>/)中以.do结尾的任何内容映射到动作servlet。

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