我想知道是否有可能声明一个Attribute属性来描述一个需要强类型的属性,并且理想情况下可以使用智能感知来选择属性。通过将成员声明为TypeType,类类型可以很好地工作。但是如何获得属性作为参数,使"PropName"不引号和强类型?
到目前为止:属性类和示例用法看起来像
[AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
public class MyMeta : Attribute{
public Type SomeType { get; set; } // works they Way I like.
// but now some declaration for a property that triggers strong typing
// and ideally intellisense support,
public PropertyInfo Property { get; set; } //almost, no intellisence type.Prop "PropName" is required
public ? SomeProp {get;set;} // <<<<<<< any ideas of nice type to define a property
}
public class Example{
[MyMeta(SomeType = typeof(SomeOtherClass))] //is strongly typed and get intellisense support...
public string SomeClassProp { get; set; }
[MyMeta(SomeProp = Class.Member)] // <<< would be nice....any ideas ?
public string ClassProp2 { get; set; }
// instead of
[MyMeta(SomeProp = typeof(T).GetProperty("name" )] // ... not so nice
public string ClassProp3 { get; set; }
}
编辑:为了避免使用属性名字符串,我构建了一个简单的工具来保持编译时间检查,同时存储和使用属性名的地方作为字符串。
的想法是,您可以通过其类型和名称快速引用属性,并使用像resharper这样的智能感知帮助和代码完成。然而,将STRING传递给工具。
I use a resharper template with this code shell
string propname = Utilites.PropNameAsExpr( (SomeType p) => p.SomeProperty )
表示
public class Utilities{
public static string PropNameAsExpr<TPoco, TProp>(Expression<Func<TPoco, TProp>> prop)
{
//var tname = typeof(TPoco);
var body = prop.Body as System.Linq.Expressions.MemberExpression;
return body == null ? null : body.Member.Name;
}
}
不,不可能。您可以使用typeof
作为类型名,但必须使用字符串作为成员名。这是你所能得到的:
[AttributeUsage(AttributeTargets.Property, AllowMultiple = false)]
public class MyMeta : Attribute{
public Type SomeType { get; set; }
public string PropertyName {get;set;}
public PropertyInfo Property { get { return /* get the PropertyInfo with reflection */; } }
}
public class Example{
[MyMeta(SomeType = typeof(SomeOtherClass))] //is strongly typed and get intellisense support...
public string SomeClassProp { get; set; }
[MyMeta(SomeType = typeof(SomeOtherClass), PropertyName = "SomeOtherProperty")]
public string ClassProp2 { get; set; }
}