分割逗号分隔的值，并将它们映射到SQLite中的原始ID

Question

我有一个名为articles的表，其中包含以下格式的数据:

id|categories
--+----------
1|123,13,43
2|1,3,15
3|9,17,44,18,3

出于测试目的，您可以使用以下SQL命令创建此表:

CREATE TABLE articles(id INTEGER PRIMARY KEY, categories TEXT);
INSERT INTO articles VALUES(1, '123,13,43'), (2, '1,3,15'), (3, '9,17,44,18,3');

现在我想分割categories列的值，以便生成如下表:

id|category
--+--------
1|123
1|13
1|43
2|1
2|3
2|15
3|9
3|17
3|44
3|18
3|3

如您所见，我希望将原始表转换为First标准格式。

我已经知道如何以这种方式拆分一行。下面的代码示例只取第二行(即id=2的那一行)，并按所需的方式拆分它们:

WITH split(article_id, word, str, offsep) AS
(
    VALUES
    (
        2,
        '',
        (SELECT categories FROM articles WHERE id=2),
        1
    )
    UNION ALL
    SELECT
        article_id,
        substr(str, 0, CASE WHEN instr(str, ',') THEN instr(str, ',') ELSE length(str)+1 END),
        ltrim(substr(str, instr(str, ',')), ','),
        instr(str, ',')
        FROM split
        WHERE offsep
) SELECT article_id, word FROM split WHERE word!='';

当然，这是非常不灵活的，因为文章ID需要硬编码。所以，现在我的问题是:我必须在上面的SQLite代码中添加或更改什么才能使它对所有行进行操作并输出所需的结果?

Answer 1

经过一番摸索，我终于自己想出了解决办法。它还处理将''或NULL作为categories值的行:

-- create temporary table which buffers the maximum article ID, because SELECT MAX can take a very long time on huge databases
DROP TABLE IF EXISTS max_article_id;
CREATE TEMP TABLE max_article_id(num INTEGER);
INSERT INTO max_article_id VALUES((SELECT MAX(id) FROM articles));
WITH RECURSIVE split(article_id, word, str, offsep) AS
(
    VALUES ( 0, '', '', 0 )                                      -- begin with dummy article 0 (which does not actually exist) to avoid code duplication
    UNION ALL
    SELECT
        CASE WHEN offsep==0 OR str IS NULL
            THEN article_id+1                                    -- go to next article if the current one is finished
            ELSE article_id                                      -- and keep the current one in the opposite case
        END,
        CASE WHEN offsep==0 OR str IS NULL
            THEN ''
            ELSE substr(str, 0, CASE WHEN instr(str, ',') THEN instr(str, ',') ELSE length(str)+1 END)
        END,
        CASE WHEN offsep==0 OR str IS NULL                       -- when str==NULL, then there has been a NULL value for the categories cell of the current article
            THEN (SELECT categories FROM articles WHERE id=article_id+1)
            ELSE ltrim(substr(str, instr(str, ',')), ',')
        END,
        CASE WHEN offsep==0 OR str IS NULL                       -- offsep==0 means that the splitting was finished in the previous iteration
            THEN 1                                               -- offsep==1 means that splitting the categories for a new article will begin in the next iteration
            ELSE instr(str, ',')                                 -- the actual string splitting stuff is explained and taken from here: http://stackoverflow.com/a/32051164
        END
        FROM split
        WHERE article_id<=(SELECT * FROM max_article_id)         -- stop getting new articles when the maximum article ID is reached
) SELECT article_id, word AS category FROM split WHERE word!=''; -- only select article_id and word from the result to use output the desired table layout

Answer 2

嗨，这可能是几年晚了，但我有一个更简单的解决方案，使用我的修订答案在如何分割逗号分隔值在SQLite?

CREATE TABLE articles(id INTEGER PRIMARY KEY, categories TEXT);
INSERT INTO articles VALUES(1, '123,13,43'), (2, '1,3,15'),
(3, '9,17,44,18,3'), (4, ''), (5, NULL);
WITH split(id, category, str) AS (
    SELECT id, '', categories||',' FROM articles
    UNION ALL SELECT id,
    substr(str, 0, instr(str, ',')),
    substr(str, instr(str, ',')+1)
    FROM split WHERE str
) SELECT id, category FROM split WHERE category ORDER BY id;

输出如您所愿:

id|category
1|123
1|13
1|43
2|1
2|3
2|15
3|9
3|17
3|44
3|18
3|3