我试图通过使用晚期静态绑定来执行每个类的initialize()
方法:
class BaseClass
{
protected static $initialized = false;
public static function find()
{
static::initialize();
//TODO search entries and return as instances...
}
protected static function initialize()
{
if (static::$initialized)
return;
echo 'Initializing ', static::class, '<br/>';
//do important stuff
static::$initialized = true;
}
}
class Child1 extends BaseClass {}
class Child2 extends BaseClass {}
$initialized
属性在扩展类中共享。
Child1::find(); //Outputs 'Initializing Child1', as expected
Child2::find(); //Doesn't execute 'initialize()' because
//$initialized property was set to true by Child1
//Expected: 'Initializing Child2'
有什么简单的方法可以实现它吗?
您可以使用类名称为密钥来更改$初始化为数组(如注释中的建议(:
class BaseClass
{
protected static $initialized = [];
public static function find()
{
return static::initialize();
}
protected static function initialize()
{
$class_name = static::class;
if (!empty(static::$initialized[$class_name])) {
return static::$initialized[$class_name];
}
echo 'Initializing ', $class_name, '<br/>';
//do important stuff
static::$initialized[$class_name] = new static();
// do another important stuff and return instance
return static::$initialized[$class_name];
}
}
class Child1 extends BaseClass {}
class Child2 extends BaseClass {}