Hibernate:插入多个:错误列不能为空

Question

大家，当插入实体数量多到一位时，我有一个问题。问题：我要插入一个新记录：StaffID，类型，原因。但是表记录和员工之间的关系很多，因此我不知道如何在此表中使用> dto dto 的Prop是StaffID或员工员工，我该如何插入。TKS这么多！

代码下面：

员工实体

@Entity
@Table(name = "STAFF")
public class Employee {
@Column(name = "DEPARTMENT_ID")
private Long departmentId;
@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(insertable = false, updatable = false)
private Department department;

记录实体

@Entity
@Table(name = "Records", catalog = "Assignment")
public class Records implements java.io.Serializable {
/**
 * 
 */
private static final long serialVersionUID = 1L;
private Long id;
private Employee Employee;
private boolean type;
private String reason;
private Date date;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "StaffId", nullable = false)
public Employee getEmployee() {
    return this.Employee;

recorddto

在控制器中，我不知道要使用哪个类，形式或DTO 公共类Recorddto {

  /*=====================================================================================================
 *===== PRIVATE PROPERTIES                                                                        =====
 *=====================================================================================================*/
/**
 * trunglq_department.ID
 */
private Long id;
/**
 * trunglq_department.Employee
 */
private Employee Employee;
/**
 * trunglq_department.type
 */
private boolean type;
/**
 * trunglq_department.reason
 */
private String reason;
/**
 * trunglq_department.date
 */
private Date date;

recordform

public class RecordForm {
/*=====================================================================================================
 *===== PRIVATE PROPERTIES                                                                        =====
 *=====================================================================================================*/
/**
 * trunglq_department.ID
 */
private Long id;
/**
 * trunglq_department.Employee
 */
private int staffId;
/**
 * trunglq_department.type
 */
private boolean type;
/**
 * trunglq_department.reason
 */
private String reason;
/**
 * trunglq_department.date
 */
private Date date;

存储库

@Override
public Long insert(Records record) {
    record.setDate(new Date());
    return (Long)super.insert(record);
}

服务

@Override
public Long create(RecordForm recordForm) {
    recordForm.setStaffId(9);
    Records record = (Records) DataTransformUtil.transform(recordForm, Records.class);
    return (Long)recordRepository.insert(record);
}

控制器

在控制器中，我不知道要使用哪个类，形式或DTO

 @PostMapping("/create")
public String index(Model model, @ModelAttribute("formRecord") RecordForm recordForm,HttpServletRequest request) {
    recordService.create(recordForm);
    return "/employee/index";
}

JSP

JSP是模态，当单击一行时，我会在表中获取数据。 在此中，数据包括：StaffID，类型，原因。 错误代码为null sextid。

form:form modelAttribute="formRecord" action="record/create"
                method="POST">
                <!-- Modal Header -->
                <div class="modal-header">
                    <h4 class="modal-title">
                        Ghi nhận nhân viên có ID:
                            <label class="idStaff"
                            style="font-size: 20px"></label>
                    </h4>
                    <button type="button" class="close" data-dismiss="modal">&times;</button>
                </div>
                <!-- Modal body -->
                <div class="modal-body">
                        <form:hidden path="staffId" class="idStaff"/>
                    <div class="custom-control custom-radio custom-control-inline">
                        <form:radiobutton path="type" class="custom-control-input"
                            id="customRadio" name="radioRecord" value="0" />
                        <label class="custom-control-label" for="customRadio">Achievement</label>
                    </div>
                    <div class="custom-control custom-radio custom-control-inline">
                        <form:radiobutton path="type" class="custom-control-input"
                            id="customRadio2" name="radioRecord" value="1" />
                        <label class="custom-control-label" for="customRadio2">Mistake</label>
                    </div>
                    <div class="form-group">
                        <label for="reason">Reason:</label>
                        <form:textarea class="form-control" rows="5" id="comment"
                            path="reason" />
                    </div>
                </div>
                <!-- Modal footer -->
                <div class="modal-footer">
                    <button type="submit" class="btn btn-success">Save</button>
                    <button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
                </div>
            </form:form>

错误代码

java.sql.SQLIntegrityConstraintViolationException: Column 'StaffId' cannot be null

Answer 1

您的员工Pojo缺少StaffID（PK）。另外，如果您已经有一个部门变量，为什么要有部门ID？

您的表格可能具有suffs_id，dections_id，staff_name等，因此，对于许多比一，您只需要添加外国密钥参考，并且在pojos中，您必须确定joincolumn为dections_id。类似于您拥有的记录实体。