动态无序列表 Web 组件使用模板生成



使用模板动态生成嵌套无序<ul><li>...</li></ul>列表,所以我和输入作为Obj={}我遇到了一些问题。这是我下面的代码请帮助我...

1. index.html
<!DOCTYPE html>
<html dir="ltr" lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0, minimum-scale=1.0, maximum-scale=5.0">
<title>Stencil Component Starter</title> 
<script src="/build/mycomponent.js"></script>
</head>
<body>   
<list-component list-object='[
{title: "Point", children: [
{title: "Point"},
{title: "Point"},
{title: "Point"},
{title: "Point", children: [
{title: "Point"},
{title: "Point"},
{title: "Point"}
]}
]},
{title: "Point", children: [
{title: "Point"},
{title: "Point", children: [
{title: "Point"},
{title: "Point"},
{title: "Point"}
]},
{title: "Point"}
]},
]' > </list-component>  
</body>
</html>

问题: 我正在将嵌套对象传递给自定义 Web 组件。 在这个list.tsx文件中,我在将参数传递给函数时遇到问题buildList("?","?")...?

2. list.tsx
import { Component, Prop, State, Watch, Element } from '@stencil/core';

@Component({
tag:'list-component',
styleUrl:'./list-component.css' 
})
export class ListComponent{
@State() idName: string;   
@Prop() listObject: string;
@Element() flashElement: HTMLElement;   
private ulContent: HTMLElement;
componentWillLoad() { 
this.ulContent  = this.flashElement.querySelector('.ul-content');
this.buildList(this.ulContent,this.listObject);  
}

@Watch('listObject') 
buildList(parentElement, listObject){ 
console.log(listObject);
var i, l, list, li, ul1;
if( !listObject || !listObject.length ) { return; } 
ul1 = document.createElement('ul');
list = parentElement.appendChild(ul1);
for(i = 0, l = listObject.length ; i < l ; i++) {
li = document.createElement('li');
li.appendChild(document.createTextNode(listObject[i].title)); 
list.appendChild(li);
this.buildList(li, listObject[i].children);
} 
} 
render() {
return ( 
<div class="ul-content"></div>
);
}
}

我看到两个问题:

1:当 Stencil 调用@Watch方法时,它总是将新值和旧值作为参数传递,请参阅 https://stenciljs.com/docs/properties#prop-default-values-and-validation。这意味着您无法定义自定义参数。 您可以创建一个充当观察程序的附加函数,然后调用 buildList:

@Watch('listObject')
listObjectChanged() {
this.buildList(this.ulContent, this.listObject);
}

2:listObject是一个字符串,所以你需要先JSON.parse它,然后才能循环它(并重写它,让它成为有效的 JSON)。然后将解析的列表存储在局部变量中,并使用它来生成列表。见 https://medium.com/@gilfink/using-complex-objects-arrays-as-props-in-stencil-components-f2d54b093e85

有一种

更简单的方法可以使用 JSX 呈现该列表,而不是手动创建列表元素:

import { Component, Prop, State, Watch, Element } from '@stencil/core';
@Component({
tag: 'list-component',
styleUrl: './list-component.css'
})
export class ListComponent {
@Element() flashElement: HTMLElement;
@State() idName: string;
@Prop() listObject: string;
@State() list: any[];
@Watch('listObject')
listObjectChanged() {
this.list = JSON.parse(this.listObject);
}
componentWillLoad() {
this.listObjectChanged();
}
renderList(list) {
return list.map(list => <ul>
<li>{list.title}</li>
{list.children && this.renderList(list.children)}
</ul>
);
}
render() {
return (
<div class="ul-content">
{this.renderList(this.list)}
</div>
);
}
}

希望这有帮助。

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