从字符串数组中筛选数字，并在android中获取最后两个较大数字的索引

Question

我有一个ArrayList，它的值像[value，Sum3121，data8input，in:21:：7,7.00,9.01]，我只想提取数字，因为输出应该是这样的[3121,8.21,7,7,0.00,9.01]，然后必须升序重新排列，然后获得最后两个数字的索引，结果将是[2121]。

下面是我尝试过的代码，

for (int i = 0; i < arrayString.size(); i++) {
Pattern p = Pattern.compile("-?\d+(,\d+)*?\.?\d+?");
List<String> numbers = new ArrayList<String>();
Matcher m = p.matcher(arrayString.get(i).getvalue);
numbers.addAll(m);
for (int j = 0; j < numbers.size(); j++) {
Log.d("REMEMBERFILTER", allCollection.get(i).getTextValue());
}
}
}

Answer 1

这样做，尽管它并不完全是内存高效的，因为我正在使用另一个列表

ArrayList<String> tempList = new ArrayList<>();
for (int i = 0; i < yourArrayList.size(); i++) {
tempList.add(yourArrayList.get(i).replaceAll("[^0-9]", ""));
}
//Arrange in ascending order
Collections.sort(tempList);
//Also try to remove those indexes which has only letters with
tempList.removeAll(Arrays.asList("", null));
for (int i = 0; i < tempList.size(); i++) {
Log.d("+++++++++", "" + tempList.get(i));
}
//You can get the last two or any element by get method of list by //list.size()-1 and list.size()-2 so on 

Answer 2

这是一种方法，finalArray有两个您想要的数字：

String[] str = new String[] {"Value", "Sum3", "121", "data8input", "in:21::7", "7.00,9.01"};
StringBuilder longStringBuilder = new StringBuilder();
for (String s : str) {
longStringBuilder.append(s).append(" ");
}
String longString = longStringBuilder.toString();
String onlyNumbers = " " + longString.replaceAll("[^0-9.]", " ") + " ";
onlyNumbers = onlyNumbers.replaceAll(" \. ", "").trim();
while (onlyNumbers.indexOf("  ") > 0) {
onlyNumbers = onlyNumbers.replaceAll("  ", " ");
}
String[] array = onlyNumbers.split(" ");
Double[] doubleArray = new Double[array.length];
for (int i = 0; i < array.length; i++) {
try {
doubleArray[i] = Double.parseDouble(array[i]);
} catch (NumberFormatException e) {
e.printStackTrace();
doubleArray[i] = 0.0;
}
}
Arrays.sort(doubleArray);
int numbersCount = doubleArray.length;
Double[] finalArray;
if (numbersCount >= 2) {
finalArray = new Double[]{doubleArray[numbersCount - 2], doubleArray[numbersCount - 1]};
} else if (numbersCount == 1) {
finalArray = new Double[]{ doubleArray[0]};
} else {
finalArray = new Double[]{};
}
for (Double number : finalArray) {
System.out.println(number);
}