输入三角形边的长度和输出三角形类型。不起作用

Question

所以，这是我的代码，python似乎没有以粗体运行这些行。基本上，它是一个代码，用户输入三个三角形边的三个长度，它输出三角形的类型(等边、等腰、斜角(不起作用。请帮帮我(或右(。

x= input (" Length of side 1 =  ")
y= input ("Length of side 2 =  ")
z= input ("Length of side 3 = ")
x= float (x)
y= float (y)
z= float (z)
flag=0
if x==y==z:
print ("This is an equilateral triangle")
flag=1
if x>y and x>z and (x**2) == ((z**2) + (y**2)):
print ("This is a right triangle")
flag=1
if z>y and z>x and (z**2) ==((x**2) + (y**2)):
print ("This is a right triangle")
flag=1
if y>z and y>x and (y**2) == ((z**2) + (x**2)):
print ("This is a right triangle")
flag=1
**if x!=z!=y and flag==0:
print("This triangle is scalene")**
if x==z and x!= y:
print ("This triangle is isosceles")
if x==y and x!= z:
print ("This triangle is isosceles")
if z==y and z!= x:
print ("This triangle is isosceles")

Answer 1

一些小的改进来帮助你学习：

def identify_triangle(x, y, z):
def tri_print(tri_type):
print("This is an {} triangle".format(tri_type))
if all([x==y, x==z]):
triangle_type = "equilateral"
elif any([
all([x>y, x>z, (x**2)==((z**2)+(y**2))]),
all([z>y, z>x, (z**2)==((x**2)+(y**2))]),
all([y>z, y>x, (y**2)==((z**2)+(x**2))]),
]):
triangle_type = "right"
elif all([x!=z, z!=y, x!=y]):
triangle_type = "scalene"
elif any([
all([x==z, x!=y]),
all([x==y, x!=z]),
all([z==y, z!=x]),
]):
triangle_type = "isosceles"
else:
triangle_type = "Unknown"
tri_print(triangle_type)
return triangle_type
x= float(input("Length of side 1 = "))
y= float(input("Length of side 2 = "))
z= float(input("Length of side 3 = "))
print()
identify_triangle(x, y, z)