我有一个混合数据的XML文件,有些需要直接复制有些需要根据分隔符进行分割和复制使用xslt v 1.0
输入如下:
<class id=1>
<teacher id=100>
Some Teacher
</teacher>
<pupils>
101,boy,John;102,girl,Anna;103,boy,Tom
</pupils>
</class>
我要把它转换成这样的格式:
<class id=1>
<teacher id=100>
Some Teacher
</teacher>
<pupil id=101>
<gender id="boy">
<name>
John
</name>
</gender>
</pupil>
<pupil id=102>
<gender id="girl">
<name>
Anna
</name>
</gender>
</pupil>
<pupil id=103>
<gender id="boy">
<name>
Tom
</name>
</gender>
</pupil>
</class>
提前感谢如何处理这个
试试这个方法?
XSLT 1.0<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="pupils">
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="normalize-space(.)"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="tokenize">
<xsl:param name="text"/>
<xsl:param name="delimiter" select="';'"/>
<xsl:variable name="token" select="substring-before(concat($text, $delimiter), $delimiter)" />
<xsl:if test="$token">
<pupil id="{substring-before($token, ',')}">
<gender id="{substring-before(substring-after($token, ','), ',')}">
<name>
<xsl:value-of select="substring-after(substring-after($token, ','), ',')" />
</name>
</gender>
</pupil>
</xsl:if>
<xsl:if test="contains($text, $delimiter)">
<!-- recursive call -->
<xsl:call-template name="tokenize">
<xsl:with-param name="text" select="substring-after($text, $delimiter)"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>