将 txt 文件数据导入数组，同时过滤字符 Python 2.7

Question

您好，我想从文本文件文本导入数据.txt并将其导入到删除逗号和的数组中。文件的数据类似于以下内容：

1,2,3,4,5,6,7,8,9,0
0,9,8,7,6,5,4,3,2,1
3,5,2,7,6,5,5,2,6,1
1,2,3,4,5,6,7,8,9,0
0,9,8,7,6,5,4,3,2,1
0,9,8,7,6,5,4,3,2,1
3,5,2,7,6,5,5,2,6,1

到目前为止，我的代码如下：

def ReadFile():
  myFile = open('text.txt','r')
  lines = myFile.readlines()
  print lines #print raw data
  lines[:] = [line.rstrip('n') for line in lines]
  print lines #print lines after removing n
  lines = lines.replace(",", "")
  print lines #print after removing commas
  lines = map(int, lines)
  print lines #print lines after converting to int

我无法删除逗号，也无法转换为 int。错误消息如下：

AttributeError: 'list' object has no attribute 'replace'
ValueError: invalid literal for int() with base 10: '1,2,3,4,5,6,7,8,9,0'

谢谢

Answer 1

你使这变得比必要的更难：

def ReadFile():
    array = []
    with open('textfiledata.txt', 'rt') as myFile:
        for line in myFile:
            array.append(map(int, line.split(',')))
    return array
print ReadFile()

输出：

[[1, 2, 3, 4, 5, 6, 7, 8, 9, 0],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [3, 5, 2, 7, 6, 5, 5, 2, 6, 1],
 [1, 2, 3, 4, 5, 6, 7, 8, 9, 0],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [3, 5, 2, 7, 6, 5, 5, 2, 6, 1]]

Answer 2

试试这个：

def read_file(filename):
    with open(filename) as f:
        return [ [int(item) for item in line.split(',')]
                            for line in f ]
>>> print read_file('text.txt')
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 0],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [3, 5, 2, 7, 6, 5, 5, 2, 6, 1],
 [1, 2, 3, 4, 5, 6, 7, 8, 9, 0],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [0, 9, 8, 7, 6, 5, 4, 3, 2, 1],
 [3, 5, 2, 7, 6, 5, 5, 2, 6, 1]]

Answer 3

使用生成器，您可以执行以下操作：

# create a generator
def ReadFile():
   with open('text.txt','r') as myFile:
       for line in myFile:
           # send out the line just processed
           yield map(int, line.strip().split(','))
# cast the generator to a  list for printing
print list(ReadFile())

Answer 4

您可以执行以下操作，因为您可以使用逗号和 int 强制转换：

for i in lines:
     my_list.append(i)