我正试图通过ftp上传文本文件,当我运行程序时,它会清空我的文件,然后上传。我不知道为什么。。。可能会改写或其他什么。。。这是我的代码:
这是主类
/* Create Object Instance */
ftp ftpClient = new ftp(@"ftp://sportcaffe.me", "sport***", "*****");
/* Upload a File */
ftpClient.upload("public_html/test.txt", @"C:UsersLazarDesktoptest.txt");
这里是ftp类的函数代码:
/* Upload File */
public void upload(string remoteFile, string localFile)
{
try
{
/* Create an FTP Request */
ftpRequest = (FtpWebRequest)FtpWebRequest.Create(host + "/" + remoteFile);
/* Log in to the FTP Server with the User Name and Password Provided */
ftpRequest.Credentials = new NetworkCredential(user, pass);
/* When in doubt, use these options */
ftpRequest.UseBinary = true;
ftpRequest.UsePassive = true;
ftpRequest.KeepAlive = true;
/* Specify the Type of FTP Request */
ftpRequest.Method = WebRequestMethods.Ftp.UploadFile;
/* Establish Return Communication with the FTP Server */
ftpStream = ftpRequest.GetRequestStream();
/* Open a File Stream to Read the File for Upload */
FileStream localFileStream = new FileStream(localFile, FileMode.Create);
/* Buffer for the Downloaded Data */
byte[] byteBuffer = new byte[bufferSize];
int bytesSent = localFileStream.Read(byteBuffer, 0, bufferSize);
/* Upload the File by Sending the Buffered Data Until the Transfer is Complete */
try
{
while (bytesSent != 0)
{
ftpStream.Write(byteBuffer, 0, bytesSent);
bytesSent = localFileStream.Read(byteBuffer, 0, bufferSize);
}
}
catch (Exception ex) { MessageBox.Show(ex.ToString()); }
/* Resource Cleanup */
localFileStream.Close();
ftpStream.Close();
ftpRequest = null;
}
catch (Exception ex) { MessageBox.Show(ex.ToString()); }
return;
}
没有错误和警告。。。
首先我在我的文件中写了一些东西并保存,然后当我运行程序时,我的文件是空的,empy文件已经上传。。。
我用了这个代码http://www.codeproject.com/Tips/443588/Simple-Csharp-FTP-Class
FileStream localFileStream = new FileStream(localFile, FileMode.Create);
我希望我不需要太清楚地拼写出来,但上面的行被告知创建文件。引用文档:"指定操作系统应该创建一个新文件。如果文件已经存在,它将被覆盖。"
http://msdn.microsoft.com/en-us/library/system.io.filemode(v=vs.110).aspx有一个选项列表,您可以在此处使用。FileMode.Open
应该适合您的需要(它将打开文件,如果文件不存在,则抛出异常)。
已解决
FileStream localFileStream=新的FileStream(localFile,FileMode.Create);替换FileMode。按FileMode创建。打开