我想过滤嵌套ng-repeat中的对象。
.HTML：
<div ng-controller="MyController">
<input type="text" ng-model="selectedCityId" />
<ul>
<li ng-repeat="shop in shops">
<p ng-repeat = "locations in shop.locations | filter:search" style="display: block">
City id: {{ locations.city_id }}
<span style="padding-left: 20px; display: block;" ng-repeat="detail in locations.details | filter:item">Pin code: {{detail.pin}}</span>
</p>
</li>
</ul>
控制器：
var myApp = angular.module('myApp', []);
myApp.controller('MyController', function ($scope) {
$scope.search = function (location) {
if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
return true;
}
if (location.city_id === parseInt($scope.selectedCityId)) {
return true;
}
};
$scope.item = function (detail) {
if ($scope.selectedCityId === undefined || $scope.selectedCityId.length === 0) {
return true;
}
if (detail.pin == parseInt($scope.selectedCityId)) {
return true;
}
};
$scope.shops =
[
{
"category_id":2,
"locations":[
{
"city_id":368,
"details": [{
"pin": 627718,
"state": 'MH'
}]
}
]
},
{
"name":"xxx",
"category_id":1,
"locations":[
{
"city_id":400,
"region_id":4,
"details": [{
"pin": 627009,
"state": 'MH'
},{
"pin": 129818,
"state": 'QA'
}]
},
]
},
];
});
这是小提琴：
http://jsfiddle.net/suCWn/210/
我想在 ng-repeat 中使用多个过滤器。
示例：每当用户在输入框中输入 ID 时。该列表应根据城市 ID 或密码进行过滤。如果用户输入"129818"，它应该显示129818的PIN码结果及其父城市ID同样，如果用户输入 400，列表应筛选并显示包含 400 的 cityID 结果及其子 PIN 码。
编辑：
更新代码 http://codepen.io/chiragshah_mb/pen/aZorMe?editors=1010]
首先，不得使用匹配的详细信息筛选位置。在search过滤器中使用类似以下内容：
$scope.search = function (location) {
var id = parseInt($scope.selectedCityId);
return isNaN(id) || location.city_id === id ||
location.details.some(function(d) { return d.pin === id });
};
要显示按 cityID 过滤的详细信息，您必须找到父location并检查它是否已过滤。
$scope.item = function (detail) {
var id = parseInt($scope.selectedCityId);
return isNaN(id) || detail.pin === id || locationMatches(detail, id);
};
function locationMatches(detail, id) {
var location = locationByDetail(detail);
return location && location.city_id === id;
}
function locationByDetail(detail) {
var shops = $scope.shops;
for(var iS = 0, eS = shops.length; iS != eS; iS++) {
for(var iL = 0, eL = shops[iS].locations.length; iL != eL; iL++) {
if (shops[iS].locations[iL].details.indexOf(detail) >= 0) {
return shops[iS].locations[iL];
}
}
}
}
编辑 另一个更灵活的解决方案是从ngRepeats中删除所有过滤器，并以您在ngChange上调用的搜索文本的方法进行过滤。以下是此方法的基本结构。
myApp.controller('MyController', function($scope, $http) {
var defaultMenu = [];
$scope.currentMenu = [];
$scope.searchText = '';
$http.get(/*...*/).then(function (menu) { defaultMenu = menu; } );
$scope.onSearch = function() {
if (!$scope.searchText) {
$scope.currentMenu = defaultMenu ;
}
else {
// do your special filter logic here...
}
};
});
和模板：
<input type="text" ng-model="searchText" ng-change="onSearch()" />
<ul>
<li ng-repeat="category in currentMenu">
...
</li>
</ul>
我已经更新了你的过滤器。问题在于您的search过滤器中，您只检查city_id，您应该做的是：
- 检查键入的 ID 是否city_id
- 检查键入的 ID 是否是给定位置的子详细信息的
pid
item过滤器类似：
- 检查键入的 ID 是否是正在筛选的详细信息的
pid - 检查键入的 ID 是否是传入详细信息的父位置的
city_id
这是一个工作 jsFiddle。我希望这有所帮助。
通过简单地修改JSON以包含子项的city_id，这样您就不需要遍历它来获取父级的city_id，解决方案非常简单：
var myApp = angular.module('myApp', []);
myApp.controller('MyController', function ($scope) {
$scope.search = function (location) {
if (!$scope.selectedCityId)
return true;
//if user's input is contained within a city's id
if (location.city_id.toString().indexOf($scope.selectedCityId) > -1)
return true;
for (var i = 0; i < location.details.length; i++)
//if user's input is contained within a city's pin
if (location.details[i].pin.toString().indexOf($scope.selectedCityId) > -1)
return true;
};
$scope.item = function (detail) {
if (!$scope.selectedCityId)
return true;
//if user's input is contained within a city's id
if (detail.city_id.toString().indexOf($scope.selectedCityId) > -1)
return true;
//if user's input is contained within a city's pin
if (detail.pin.toString().indexOf($scope.selectedCityId) > -1)
return true;
};
修改后的 JSON
$scope.shops=[{"category_id":2,"locations":[{"city_id":368,"details":[{"city_id":368,"pin":627718,"state":'MH'}]}]},{"name":"xxx","category_id":1,"locations":[{"city_id":400,"region_id":4,"details":[{"city_id":400,"pin":627009,"state":'MH'},{"city_id":400,"pin":129818,"state":'QA'}]},]},];});
如果无法直接修改JSON，则可以在此 $scope.shops = ...json... 语句之后直接在此控制器中像这样修改它：
for(var i=0; i<$scope.shops.length; i++)
for(var j=0, cat=$scope.shops[i]; j<cat.locations.length; j++)
for(var k=0, loc=cat.locations[j]; k<loc.details.length; k++)
loc.details[k].city_id=loc.city_id;
工作小提琴：http://jsfiddle.net/87e314a0/
我试图使解决方案更容易理解：
索引.html ：
<div ng-controller="MyController">
<input type="text" ng-model="search.city_id" />
<ul>
<li ng-repeat="shop in shops">
<p ng-repeat = "locations in shop.locations | filter:search.city_id" style="display: block">
City id: {{ locations.city_id }}
<span style="padding-left: 20px; display: block;" ng-repeat="detail in locations.details | filter:item">Pin code: {{detail.pin}}</span>
</p>
</li>
</ul>
</div>
应用程序.js ：
var myApp = angular.module('myApp', []);
myApp.controller('MyController', function ($scope) {
$scope.shops =
[
{
"category_id":2,
"locations":[
{
"city_id":368,
"details": [{
"pin": 627718,
"state": 'MH'
}]
}
]
},
{
"name":"xxx",
"category_id":1,
"locations":[
{
"city_id":400,
"region_id":4,
"details": [{
"pin": 627009,
"state": 'MH'
},{
"pin": 129818,
"state": 'QA'
}]
},
]
},
];
});
这是小提琴：我的解决方案