尝试解决错误"Ambiguous reference to member 'subscript'"

Question

首先创建一些列表:

let day0 = [0] as NSArray
let day1 = [0, 8, 2, 3, 4] as NSArray
let day2 = [0, 1, 2, 3, 4] as NSArray
let day3 = [0, 1, 2, 3, 4] as NSArray
let day4 = [0, 1, 2, 3, 4] as NSArray
let month0 = [0] as NSArray
let january = [day0, day1, day2, day3, day4] as NSArray
let february = [day0, day1, day2, day3, day4] as NSArray
let march = [day0, day1, day2, day3, day4] as NSArray
let april = [day0, day1, day2, day3, day4] as NSArray
let may = [day0, day1, day2, day3, day4] as NSArray
let june = [day0, day1, day2, day3, day4] as NSArray
let july = [day0, day1, day2, day3, day4] as NSArray
let august = [day0, day1, day2, day3, day4] as NSArray
let september = [day0, day1, day2, day3, day4] as NSArray
let october = [day0, day1, day2, day3, day4] as NSArray
let november = [day0, day1, day2, day3, day4] as NSArray
let december = [day0, day1, day2, day3, day4] as NSArray
let calendar = [month0, january, february, march, april, may, june, july, august, september, october, december] as NSArray

然后我尝试返回一个元素:

@IBAction func SetVariablesButton(sender: UIButton)
{
    var result = calendar[1][1][1] as String
    BedTimeLabel.text = String(result)
}

然后得到错误。我尝试了各种更改，例如

let day0 = [0] as! NSArray

和

let day0 = [0] as Array<T>

但这些都不起作用。我最初根本没有强制转换变量，但在研究了常见问题之后，常见的解决方案是强制转换变量，这样编译器就可以理解发生了什么。我使用Xcode 8与Swift 2.3

Answer 1

首先将虚拟月份month0声明为[[0]]，以获得与其他月份相同的类型。

然后删除所有类型转换。

let day0 = [0]
let day1 = [0, 8, 2, 3, 4]
let day2 = [0, 1, 2, 3, 4]
let day3 = [0, 1, 2, 3, 4]
let day4 = [0, 1, 2, 3, 4]
let month0 = [[0]]
let january = [day0, day1, day2, day3, day4]
let february = [day0, day1, day2, day3, day4]
let march = [day0, day1, day2, day3, day4]
let april = [day0, day1, day2, day3, day4]
let may = [day0, day1, day2, day3, day4]
let june = [day0, day1, day2, day3, day4]
let july = [day0, day1, day2, day3, day4]
let august = [day0, day1, day2, day3, day4]
let september = [day0, day1, day2, day3, day4]
let october = [day0, day1, day2, day3, day4]
let november = [day0, day1, day2, day3, day4]
let december = [day0, day1, day2, day3, day4]
let calendar = [month0, january, february, march, april, may, june, july, august, september, october, december]

编译器可以推断出calendar为[[[Int]]]。

现在你可以写

var result = String(calendar[1][1][1])